Answer:
6 bowls of ramen eaten by you & your friend
Step-by-step explanation:
The question appears pretty choppy for me. I'll answer what I think you're asking and update in the comments if needed.
Imagine that you and a friend go to a local ramen shop for dinner at this restaurant, each regular bowl of ramen is $7.25. Drinks are $1.50 each. How many regular bowls of ramen did you and your friend eat if you ordered 2 drinks each and your total was $49.50?
a. Write an equation to represent the situation using x to represent the # of bowls you and your friend ate.
4($1.50) + $7.25x = $49.50
6 + 7.25x = 49.50
subtract 6 from both sides
7.25x = 43.50
divide both sides by 7.25
x = 6
Checking the math:
4(1.5) + 6(7.25) = 6 + 43.50 = 49.50
4 drinks, 6 bowls of ramen for $49.50
Answer:
C
Step-by-step explanation:
You can divide all the other answers by the same number and get 3/8 except C because there is no common number they both share.
A. Is the attached image. The slope is 7.5x
b. 1 = 7.5x
x = 1.33333…
This is hours so we must multiply this by 60
x = 8 min
Not drake!
m=number of members
n=number of nonmembers
n+m=25
cost=550=20m+25n
simplify by dividing by 5
110=4m+5n
so we have
n+m=25 and
5n+4m=110
multiply first eequation by -4 and add to second equation
-4n-4m=-100
<u>5n+4m=110+</u>
n+0m=10
n=10
subsitute
n+m=25
10+m=25
m=15
15 members
10 non-members
Answer: a example
Step-by-step explanation: hope this will help you
