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crimeas [40]
3 years ago
11

JOHN HAD 2/3 OF HIS HOMEWORK COMPLETE, SARAH HAD 5/10, ALEX 7/8, AND MICHELLE 1/2. WHO COMPLETED THE MOST OF THE HOMEWORK ASSIGN

MENT?
A. ALEX
B. MICHELLE
C. SARAH
D. JOHN
Mathematics
1 answer:
Lemur [1.5K]3 years ago
7 0
<span>We can either calculate each fraction and compare the results, or bring all of the fractions to a common denominator by finding the smallest common multiple for the fractions' denominators (3, 10, 8, 2), which is 3 * 2^3 * 5 = 120. Thus we must amplify each fraction so that its denominator becomes 120. 2/3 becomes 40/120, 5/10 becomes 60/120, 7/8 becomes 105/120 and 1/2 becomes 60/120. We can clearly see now that the largest of these fraction is the third (105/120). So the answer is C. Sarah.</span>
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Petrina had a piece of red ribbon that measured 2.4 m long. she also had a piece of blue ribbon which was 7 8 m long. what was t
katen-ka-za [31]

The total length of red and blue ribbons is 10.2 m.

Given that, the length of the red ribbon =2.4 m and the length of the blue ribbon =7.8 m.

<h3>How to add two decimals?</h3>

Adding decimals is similar to the usual addition of whole numbers. We know that a decimal number is a number with a whole number part and a fractional part which is separated by a decimal point.

Now, the length of the red ribbon + the length of the blue ribbon=2.4+7.8

=10.2 m

Therefore, the total length of red and blue ribbons is 10.2 m.

To learn more about the addition of decimals visit:

brainly.com/question/17612968.

#SPJ4

7 0
2 years ago
Type the correct answer in each box. Use numerals instead of words. For this question, any answer that is not a whole number sho
egoroff_w [7]

Answer:

Step-by-step explanation:

Since we are not given the value of P, |Q|, R and S, we can as well assume values for them for the sake of this question.

Let P = 5, |Q| = 6, R =7 |S| = 2

Note that since Q and S are in modulus sign, they can return both positive and negative values.

P+Q = 5 + 6 (note that the positive value of Q is used since we need the greatest value of P+Q)

P+Q = 11

Hence the greatest value of P+Q is 11

For the least value of P+Q, we will use the negative value of Q as shown

P+Q = 5+(-6)

P+Q = 5-6

P+Q = -1

Hence the least value of P+Q is -1

Similarly:

R+S = 7 + 2 (note that the positive value of S is used since we need the greatest value of R+S)

R+S = 9

Hence the greatest value of R+S is 9

For the least value of R+S, we will use the negative value of S as shown

R+S = 5+(-2)

R+S = 5-3

R+S = 2

Hence the least value of P+Q is 2

NOTE THAT THIS ARE ASSUMED VALUES. ALL YOU NEED IS TO PLUG IN THE VALUES OF P, Q and R THAT YOU HAVE IN CASE THE VALUES DIFFERS.

5 0
3 years ago
HELP !! THIS IS MY LAST ONE !!
Pachacha [2.7K]

Answer:

B, A, C, I

Step-by-step explanation:

1. y= -2x-7

2. y= -1/3x +0

3. y= -2x-4

4. y= -1/3x-1

This is what I got, is the code supposed to make a word?

4 0
3 years ago
Please help i really need it !!!!
Vika [28.1K]
C, i think you forgot an x
(x+11)+(x-7)
x+11+x-7
x+x+4
2x+4
4 0
3 years ago
a system of equations is shown below 7x + 3y= 22. 3x - 3y =18 what is the solution to the system of equations​
Tju [1.3M]

4,-2

distribute and combine like terms

5 0
2 years ago
Read 2 more answers
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