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3 years ago

What is the least common denominator between 15 and 40?

1 answer:

5 0

3 is the least common denominator . To find the least common denominator you list all the factors of both numbers and find the smallest one they both have in common beside one.

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70 POINTS! ∆ABC is reflected across the x-axis, then rotated 90° clockwise about the origin, and finally reflected across the li

madam [21]

Answer:

A'(1, 1); B'(3, 2); C'(1, 2)

Step-by-step explanation:

The original points are A(1,1 ), B(2, 3) and C(2, 1).

Reflecting the triangle across the x-axis will negate every y-coordinate; this maps

(1, 1)→(1, -1); (2, 3)→(2, -3); (2, 1)→(2, -1)

Rotating the figure 90° clockwise about the origin switches the x- and y-coordinates and negates the x-coordinate; this maps

(1, -1)→(-1 -1); (2, -3)→(-3, -2); (2, -1)→(-1, -2)

Reflecting across the line y=x will negate both the x- and y-coordinates; this maps

(-1, -1)→(1, 1); (-3, -2)→(3, 2); (-1, -2)→(1, 2)

3 0

3 years ago

Read 2 more answers

An airplane climbs at an angle of 11 with the ground

harkovskaia [24]

What's the question?

3 0

3 years ago

Please solve these questions

balu736 [363]

Step-by-step explanation:

x² + 4x + 3

(x+1)(x+3)

...... .

3 0

4 years ago

What is the missing step in the given proof? Help me out with my math homework please!

kari74 [83]

Answer: The missing step is,

m∠OCP ≅ m∠ABC because corresponding angles made by the same transversal on the parallel lines are congruent.

Step-by-step explanation:

Given : $AC \parallel BD$ , $AB \parallel CD$

And, $AC \perp CD$

We have to Prove : Angle PCQ is complementary to angle ABC

⇒ $m\angle PCQ + m\angle ABC = 90^{\circ}$

Proof: Since, $AC \perp CD$

⇒ $m\angle OCQ = 90^{\circ}$

But, $m\angle OCQ = m\angle OCP +m\angle PCQ$ ( By angle addition postulate )

⇒ $m\angle OCP +m\angle PCQ = 90^{\circ}$ ( By transitive property of equality )

Since, $AC \parallel BD$ ,

⇒ $\angle OCP\cong \angle ABC$ ( corresponding angles made by the same transversal are congruent)

⇒ $m\angle OCP = m\angle ABC$ ( By the definition of congruent angles )

This leads,

$m\angle ABC +m\angle PCQ = 90^{\circ}$ ( by the transitive property of equality )

Thus, by the definition of complementary angles,

Angle PCQ is complementary to angle ABC

Hence proved.

5 0

3 years ago

Read 2 more answers

Calculate the rate of change

bonufazy [111]

Answer is in the photo. I can't attach it here, but I uploaded it to a file hosting. link below! Good Luck!

tinyurl.com/wpazsebu

7 0

3 years ago