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bogdanovich [222]
3 years ago
9

What is the value of y in the equation 2(2y − 16) = 0?

Mathematics
2 answers:
anastassius [24]3 years ago
7 0
2(2y − 16) = 0 start
<span>2y−16=0 divide both sides by 2
</span><span><span>2y=16 add 16 to both sides
y=8 divide by 7

your answer is y=8</span></span>
Mariana [72]3 years ago
5 0
We first have to distribute the outside 2. That means we have to multiply the numbers in the parentheses by the outside 2.
2*2y is 4y and 2*16 is 32.
So now we have 4y-32=0
Now we have to combine like terms, basically.
So we do inverse operation, the opposite operation. So let's add 32 to the 0. That's obviously 32.
So 4y=32. We do inverse operation again. So we divide 32/4. We get 8.
And 8 is our answer. 8=y

Hope I helped :)
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What is the standard error of the sampling distribution of sample proportion?.
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Answer:

√ (p(1-p) / n)

Step-by-step explanation:

Standard Error(SE) of the Sample Proportion: √ (p(1-p) / n). Note: as the sample size increases, the standard error decreases.

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5 0
1 year ago
Find the area of the parallelogram with vertices:________.
marin [14]

Answer:

97.98

Step-by-step explanation:

The area of the parallelogram PQR is the magnitude of the cross product of any two adjacent sides. Using PQ and PS as the adjacent sides;

Area of the parallelogram = |PQ×PS|

PQ = Q-P and PS = S-P

Given P(0,0,0), Q(4,-5,3), R(4,-7,1), S(8,-12,4)

PQ = (4,-5,3) - (0,0,0)

PQ = (4,-5,3)

Also, PS = S-P

PS = (8,-12,4)-(0,0,0)

PS = (8,-12,4)

Taking the cross product of both vectors i.e PQ×PS

(4,5,-3)×(8,-12,4)

PQ×PS = (20-36)i - (16-(-24))j + (-48-40)k

PQ×PS = -16i - 40j -88k

|PQ×PS| = √(-16)²+(-40)²+(-88)²

|PQ×PS| = √256+1600+7744

|PQ×PS| = √9600

|PQ×PS| ≈ 97.98

Hence the area of the parallelogram is 97.98

3 0
3 years ago
Point C is the midpoint of a segment AB . What are the coordinates of point B, if: A(–1, 3), C( 1, –1)
a_sh-v [17]

Answer:

(3,-5)

Step-by-step explanation:

To find the x coordinate of the  midpoint, add the  x coordinates together and divide by 2

The x coordinate is

(x1+x2)/2

We know one point and the midpoint

( -1+x)/2 = 1

Multiply by 2

-1 +x = 2

Add 1

x =2+1

x=3

To find the y coordinate of the midpoint, add the  y coordinates together and divide by 2

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Multiply by 2

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Subtract 3

y = -2-3

y =-5

The other endpoint is (3,-5)

5 0
3 years ago
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