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Snowcat [4.5K]
3 years ago
6

A group of high school students reports who has a job and who plays sports. The information is presented in the following Venn d

iagram. Given that a random student does not have a job, what is the probability that the student does not play sports? Question 18 options: .7 .6 .8 .12

SAT
2 answers:
shutvik [7]3 years ago
5 0

Answer: .6

Explanation: There are 60 students in this "universe." 20 have jobs. The random student does not. So that student is in the "complement" of 40 outside the jobs circle. (16 "sports" + 24 in the field outside the circles)

Of those 40, 24 do not play sports, which is what the question specifies. The chance is then 24/40 reduced: 6/10

So the chance of the random student selected from the group of "doesn't have a job" and "doesn't play sports" is .6

makkiz [27]3 years ago
5 0
The answer is 6 :. 6
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Based on the graph given, it can be deduced from the computation that the value of y will be -8.

Point C is given as (-10 , -2)  and D = (10 , 6)

The Slope of line CD = ( 6 - (-2) /( 10 - (-10) =  8/20  = 2/5

Since EF is parallel to line CD , the slope of EF = 2/5

Equation  y  = (2/5)x  + c

5y = 2x + 5c

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= 5(-4) = 2*6  + 5c

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5y = 2x - 32

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y = -8

Therefore, the value of y is -8.

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2 years ago
what is the molarity of a solution prepared by dissolving 54.3 g of ca(no3)2 to form 355 ml of the solution?
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Answer:

The molarity of a solution prepared by dissolving 54.3 g of Calcium nitrate  into 355 mL of water is 0.9881M

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