Y/x = 9/12 = 3/4
so
y = (3/4)x . . . . . . both x and y in dollars.
Angle ADB is a right angle, which is given.
The measure of ADB is 90 degrees by definition of right angle.
The two angles are a linear pair (aka they're supplementary) by definition of linear pair (they're formed by two intersecting lines).
The measure of BDC is 90 because BDC + ADB = 180 (definition of linear pair), and ADB = 90 (given).
BDC = ADB because 90 = 90
Overall, the two triangles are congruent by SAS.
Let Xi be the random variable representing the number of units the first worker produces in day i.
Define X = X1 + X2 + X3 + X4 + X5 as the random variable representing the number of units the
first worker produces during the entire week. It is easy to prove that X is normally distributed with mean µx = 5·75 = 375 and standard deviation σx = 20√5.
Similarly, define random variables Y1, Y2,...,Y5 representing the number of units produces by
the second worker during each of the five days and define Y = Y1 + Y2 + Y3 + Y4 + Y5. Again, Y is normally distributed with mean µy = 5·65 = 325 and standard deviation σy = 25√5. Of course, we assume that X and Y are independent. The problem asks for P(X > Y ) or in other words for P(X −Y > 0). It is a quite surprising fact that the random variable U = X−Y , the difference between X and Y , is also normally distributed with mean µU = µx−µy = 375−325 = 50 and standard deviation σU, where σ2 U = σ2 x+σ2 y = 400·5+625·5 = 1025·5 = 5125. It follows that σU = √5125. A reference to the above fact can be found online at http://mathworld.wolfram.com/NormalDifferenceDistribution.html.
Now everything reduces to finding P(U > 0) P(U > 0) = P(U −50 √5125 > − 50 √5125)≈ P(Z > −0.69843) ≈ 0.757546 .
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Answer:
First statement is wrong
Step-by-step explanation:
Forgive me if I am wrong
