To find the area of the shape, you can split the shape into 2 shapes, a rectangle and a triangle. The area of a rectangle is A=l x w and the area of a triangle is A=1/2 bh. The are of the rectangle is 200 since 20 times 10 is 200. The area of the triangle is 20 times 4 divided by 2. The area of the triangle is 40. Add both areas to get the total are of 240. The area of the shape is 240.
Answer:
Step-by-step explanation:
Division by zero is undefined, so the only restriction on the domain, the values of x is that x cannot equal 9. So the domain is all real numbers except 9. Or in interval notation
x=(-oo,9),(9,+oo)
Answer:
The answer is .0001
Step-by-step explanation:
Since it is the closest value to 0, it is the largest number
NOTES:
- squared (²) means multiply that number by itself 2 times
- cubed (³) means multiply that number by itself 3 times
- square root (√) means 2 numbers multiplied by itself on the inside simplify to 1 of that number on the outside of the radical
- cubed root (∛) means 3 numbers multiplied by itself on the inside simplify to 1 of that number on the outside of the radical
Answer: (C) 41
<u>Step-by-step explanation:</u>
![\quad 6^2+\sqrt[3]{125} \\= 6 \cdot 6+\sqrt[3]{5\cdot 5 \cdot 5}\\= 36 + 5\\= 41](https://tex.z-dn.net/?f=%5Cquad%206%5E2%2B%5Csqrt%5B3%5D%7B125%7D%20%5C%5C%3D%206%20%5Ccdot%206%2B%5Csqrt%5B3%5D%7B5%5Ccdot%205%20%5Ccdot%205%7D%5C%5C%3D%2036%20%2B%205%5C%5C%3D%2041)
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Answer: (C) 10
<u>Step-by-step explanation:</u>
![\bigg(\dfrac{7}{3}\times \sqrt[3]{27}-2\bigg)\times \dfrac{1}{5} + \sqrt{81}](https://tex.z-dn.net/?f=%5Cbigg%28%5Cdfrac%7B7%7D%7B3%7D%5Ctimes%20%5Csqrt%5B3%5D%7B27%7D-2%5Cbigg%29%5Ctimes%20%5Cdfrac%7B1%7D%7B5%7D%20%2B%20%5Csqrt%7B81%7D)
![=\bigg(\dfrac{7}{3}\times \sqrt[3]{3\cdot 3 \cdot 3}-2\bigg)\times \dfrac{1}{5} + \sqrt{9\cdot 9}](https://tex.z-dn.net/?f=%3D%5Cbigg%28%5Cdfrac%7B7%7D%7B3%7D%5Ctimes%20%5Csqrt%5B3%5D%7B3%5Ccdot%203%20%5Ccdot%203%7D-2%5Cbigg%29%5Ctimes%20%5Cdfrac%7B1%7D%7B5%7D%20%2B%20%5Csqrt%7B9%5Ccdot%209%7D)
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8² = 8 · 8 = 64 11² = 11 · 11 = 121
5³ = 5 · 5 · 5 = 125 3³ = 3 · 3 · 3 = 27
![\sqrt[3]{64}=\sqrt[3]{4\cdot 4\cdot 4}=4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D%3D%5Csqrt%5B3%5D%7B4%5Ccdot%204%5Ccdot%204%7D%3D4)
![\sqrt[3]{8000}=\sqrt[3]{20\cdot 20\cdot 20}=20](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B8000%7D%3D%5Csqrt%5B3%5D%7B20%5Ccdot%2020%5Ccdot%2020%7D%3D20)
Just plug in the numbers into the equation.
m = 4a + 2c
a = adults
c = children
m = meatballs
The information given says there are 25 adults and 5 children. So now:
a = 25
and
c = 5
in the equation m = 4a + 2c
Now plug in the values.
m = 4(25) + 2(5)
m = 100 + 10
m = 110
This means that 110 meatballs are required for 25 adults and 5 children.
