All categories

3 years ago

What is 9-4(2x-1)=45?

1 answer:

5 0

9-4(2x-1)=45
Multiply -4 by 2x and -1
9-8x+4=45
Subtract 9 from both sides
-8x+4=36
Subtract 4 from both sides
-8x=32
Divide both sides by -8
Final Answer: x= -4

You might be interested in

Answer please n thank you :)

Norma-Jean [14]

Answer:45

Step-by-step explanation:

6 0

3 years ago

The Sky Ranch is a supplier of aircraft parts. Included in stock are 6 altimeters that are correctly calibrated and two that are

almond37 [142]

Answer:

For x = 0, P(x = 0) = 0.35

For x = 1, P(x = 1) = 0.54

For x = 2, P(x = 2) = 0.11

For x = 3, P(x = 3) = 0

Step-by-step explanation:

We are given that the Sky Ranch is a supplier of aircraft parts. Included in stock are 6 altimeters that are correctly calibrated and two that are not. Three altimeters are randomly selected, one at a time, without replacement.

Let X = the number that are not correctly calibrated.

Number of altimeters that are correctly calibrated = 6

Number of altimeters that are not correctly calibrated = 2

Total number of altimeters = 6 + 2 = 8

(a) For x = 0: means there are 0 altimeters that are not correctly calibrated.

This means that all three selected altimeters are correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = $^{8}C_3$

The number of ways of selecting 3 altimeters from a total of 6 altimeters that are correctly calibrated = $^{6}C_3$

So, the required probability = $\frac{^{6}C_3}{^{8}C_3}$

= $\frac{20}{56}$ = 0.35

(b) For x = 1: means there is 1 altimeter that is not correctly calibrated.

This means that from three selected altimeters; 1 is not correctly calibrated and 2 are correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = $^{8}C_3$

The number of ways of selecting 2 correctly calibrated altimeters from a total of 6 altimeters that are correctly calibrated = $^{6}C_2$

The number of ways of selecting 1 not correctly calibrated altimeters from a total of 2 altimeters that are not correctly calibrated = $^{2}C_1$

So, the required probability = $\frac{^{6}C_2 \times ^{2}C_1 }{^{8}C_3}$

= $\frac{30}{56}$ = 0.54

(c) For x = 2: means there is 2 altimeter that is not correctly calibrated.

This means that from three selected altimeters; 2 are not correctly calibrated and 1 is correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = $^{8}C_3$

The number of ways of selecting 1 correctly calibrated altimeters from a total of 6 altimeters that are correctly calibrated = $^{6}C_1$

The number of ways of selecting 2 not correctly calibrated altimeters from a total of 2 altimeters that are not correctly calibrated = $^{2}C_2$

So, the required probability = $\frac{^{6}C_1 \times ^{2}C_2 }{^{8}C_3}$

= $\frac{6}{56}$ = 0.11

(d) For x = 3: means there is 3 altimeter that is not correctly calibrated.

This case is not possible, so this probability is 0.

6 0

3 years ago

Please help this is my last day to turn in everything!!

Wewaii [24]

Answer: the second one i may be wrong but i can relate to you ❤

5 0

3 years ago

Read 2 more answers

Comment on the role that the number of observations plays in resistance.

weqwewe [10]

Answer:As the sample size increases, the impact of the misrecorded data on the mean decreases.

Step-by-step explanation:

The size of an experiment is very important in a research. Large experimental size with many sample unit helps to minimize error this is because the error is shared among all the samples but when an experimental unit is small the error is usually high.

As sample sizes increases the number of misrecorded data on the mean decreases this is because error is usually spread across all samples in a large sample size and the mean is the average performance of the samples.

6 0

3 years ago

I asked this 3 times. if anyone is good with circles in geometry, yr help would be nice plz...

UkoKoshka [18]

From the figure:

m∠A = 53°+18° = 71°

m∠B = 53°+50° = 103°

m∠C = 50°+59° = 109°

m∠D = 18°+59° = 77°

8 0

3 years ago