Answer:
D.the treatment group (placebo or reading strategies)
Step-by-step explanation:
This cognitive psychologists wants to find out if better reading strategies when taught to students would have any effect on their test scores.
So the dependent variable in this experiment would be the test scores that she wants to find from the test.
While the independent variable would be the treatment group which is the placebo or treatment. The psychologist wants to measure outcomes in this dependent variable using changes in the independent variable (placebo/treatment).
Answer:
We start with the equation:
A: 3*(x + 2) = 18
And we want to construct equation B:
B: X + 2 = 18
where I suppose that X is different than x.
Because in both equations the right side is the same thing, then the left side also should be the same thing, this means that:
3*(x + 2) = X + 2
Now we can isolate the variable x.
(x + 2) = (X + 2)/3
x = (X + 2)/3 - 2
Then we need to replace x by (X + 2)/3 - 2 in equation A, and we will get equation B.
Let's do it:
A: 3*(x + 2) = 18
Now we can replace x by = (X + 2)/3 - 2
3*( (X + 2)/3 - 2 + 2) = 18
3*( (X + 2)/3 ) = 18
3*(X + 2)/3 = 18
(X + 2) = 18
Which is equation B.
If two figures are similar, the resulting corresponding angles are always congruent.
Answer:
x = -11
Step-by-step explanation:
Considering tripled means multiplied by 3 because of tri, we know that we can use the equation 3x = -33.
To solve this we can divide both sides by 3:
3x = -33
x = -11
This gives our answer of -11.
Answer:
f(x)=(x-1)^2+5 with domain x>1 and range y>5 has inverse g(x)=sqrt(x-5)+1 with domain x>5 and range y>1.
Step-by-step explanation:
The function is a parabola when graphed. It is in vertex form f(x)=a(x-h)^2+k where (h,k) is vertex and a tells us if it's reflected or not or if it's stretched. The thing we need to notice is the vertex because if we cut the graph with a vertical line here the curve will be one to one. So the vertex is (1,5). Let's restrict the domain so x >1.
* if x>1, then x-1>0.
* Also since the parabola opens up, then y>5.
So let's solve y=(x-1)^2+5 for x.
Subtract 5 on both sides:
y-5=(x-1)^2
Take square root of both sides:
Plus/minus sqrt(y-5)=x-1
We want x-1>0:
Sqrt(y-5)=x-1
Add 1 on both sides:
Sqrt(y-5)+1=x
Swap x and y:
Sqrt(x-5)+1=y
x>5
y>1