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adelina 88 [10]
3 years ago
5

Which of the following tables represents exponential functions ?

Mathematics
1 answer:
solong [7]3 years ago
7 0
The bottom two because they rapidly go up or down super fast. If it’s an exponential function, it will start off as super low or super high and then shoot up or down rapidly
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Step-by-step explanation:

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Write the expressions without using log. Can someone please help with this?
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\bf \textit{logarithm of factors}\\\\
log_{{  a}}(xy)\implies log_{{  a}}(x)+log_{{  a}}(y)
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\textit{Logarithm of rationals}\\\\
log_{{  a}}\left(  \frac{x}{y}\right)\implies log_{{  a}}(x)-log_{{  a}}(y)
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\textit{Logarithm of exponentials}\\\\
log_{{  a}}\left( x^{{  b}} \right)\implies {{  b}}\cdot  log_{{  a}}(x)\\\\
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\bf log(m^3n)\implies log(m^3)+log(n)\implies 3log(m)+log(n)
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6 0
3 years ago
Write the answer to essential question and draw examples
Novosadov [1.4K]
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6 0
4 years ago
A man awoke to a temperature of 40 °F.By the time he arrived at work,the temperature had increased by 11°F.At lunch ,the tempera
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5 0
3 years ago
A used-car dealer sold one car at a profit of 25 percent of the dealer's purchase price for that car and sold another car at a l
Daniel [21]

Answer:

C. 1000 loss.

Step-by-step explanation:

Let x represent purchase price of each car.

We have been given that a used-car dealer sold one car at a profit of 25 percent of the dealer's purchase price for that car and sold another car at a loss of 20 percent of the dealer's purchase price for that car.

We can represent the car that dealer sold with 25% profit to find purchase price as:

x+0.25x=20,000

1.25x=20,000

\frac{1.25x}{1.25}=\frac{20,000}{1.25}

x=16,000

Therefore, the purchase price of 1st car was $16,000.

We can represent the car that dealer sold with 20% loss to find purchase price as:

x-0.20x=20,000

0.80x=20,000

\frac{0.80x}{0.80}=\frac{20,000}{0.80}

x=25,000

Therefore, the purchase price of 2nd car was $25,000.

The total purchase price of both cars would be 16,000+25,000=41,000

The total sale price of both cars 20,000+20,000=40,000.

We can see that the sale price of both car is less than purchase price by $1000, so the dealer got a loss of $1000.

Therefore, the dealer's total loss, in dollars, for the two transactions combined was 1000 and option C is the correct choice.

4 0
3 years ago
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