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Pepsi [2]
3 years ago
12

Can anyone thats really extremely excellent at math, history and english please help me out with my questions. Truly need help.

Please only answer if you know how to. ( Just click on my name and go to my questions) answer.​
Mathematics
1 answer:
expeople1 [14]3 years ago
7 0

Answer:

Meeeeeeeeeeeeeeeeeeeeeee

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Plot the xintercept of the function f(x)=(x+4)^2
Aleks [24]

Answer:

aaslee qwcvedrqpa mu  lroo vmtgdlrefu  u

ml

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
Use a system of equations to solve this problem. Dr. Graham currently has two acid solutions. She only has a 60% acid solution a
Natalka [10]
<span>Dr. Graham currently has two acid solutions.
60% acid AND 20% acid </span>
Dr. Graham needs 30 L of a 50% acid solution
We set up 2 equations in which s = 60% acid and t = 20% acid
A) s + t = 30
B) .60s + .20t = (.50 * 30)
We multiply equation A by -.20
A) = -.20s -.20t = -6 then we add it to B)
B) .60s + .20t = 15
.40s = 9
s = 22.5
t = 7.5
So, she needs to mix 22.5 liters of 60% acid with 7.5 liters of 20% acid.

Source:
http://1728.org/mixture.htm


4 0
3 years ago
I need help ASAP please help me
azamat

Answer:

3x+50=6x-10

Step-by-step explanation:

set them equal to each other and solve for x. I have no paper on me rn to help you, hope this helps tho  

3 0
3 years ago
Can you answer this?
ratelena [41]
I’m positive it’s thee third one
8 0
4 years ago
The mean age at which the population of babies first stand without support is normally distributed with a mean of 13.20 months w
Veseljchak [2.6K]

Answer:

0.00621

Step-by-step explanation:

We solve the above question using the

Z score formula. This is given as:

z = (x-μ)/σ/√n

where

x is the raw score = 12.20 or earlier

This means x ≤ 12.20

μ is the population mean = 13.20

σ is the population standard deviation = 2

n is the random number of samples = 25

z = 12.2 - 13.2/2/√25

z = -1/2/5

z = -1/0.4

z = -2.5

Probability value from Z-Table:

P(x≤ 12.2) = 0.0062097

Approximately = 0.00621

Therefore, the probability of randomly selecting a sample of 25 children who stood on their own by the average age of 12.2 months or earlier is 0.00621

3 0
3 years ago
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