Given:
The population, P, of six towns with time t in years are given by the following exponential equations:
(i) 
(ii) 
(iii) 
(iv) 
(v) 
(vi) 
To find:
The town whose population is decreasing the fastest.
Solution:
The general form of an exponential function is:
Where, a is the initial value, b is the growth or decay factor.
If b>1, then the function is increasing and if 0<b<1, then the function is decreasing.
The values of b for six towns are 1.08, 1.12, 0.9, 1.185, 0.78, 0.99 respectively. The minimum value of b is 0.78, so the population of (v) town is decreasing the fastest.
Therefore, the correct option is b.
<span>35.3529411765 that is the answer
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I think the answer is -2
Following the rule of “rise over run”, the fraction form of the gradient it 8 over 1 (8/1)
This means you move up 8 units, and move across 1 unit.
The final coordinate is (-1, -2)
V = -2
Hope this helps!
9514 1404 393
Answer:
- $10,000 at 5%
- $22,000 at 6%
Step-by-step explanation:
Let x represent the amount invested at 6%. Then 32000-x is the amount invested at 5%, and the total interest earned is ...
0.06x +0.05(32000 -x) = 1820
0.01x +1600 = 1820 . . . . simplify
0.01x = 220 . . . . . . . . . . subtract 1600
x = 22,000 . . . . . . . . . . . multiply by 100
32000 -x = 10,000
Phyllis invested $22,000 at 6% and $10,000 at 5%.
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