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cupoosta [38]
3 years ago
8

Tell whether the relation is a function.

Mathematics
2 answers:
pshichka [43]3 years ago
8 0

Answer:

Step-by-step explanation:

The easiest way to tell if a relation is a function is to look at the x coordinates.  If none of them are the same in the set, then the relation is a function.  If any of the x values are used more than once in the set, it is only a relation.  This set uses -3 two times, so it is a relation.

PilotLPTM [1.2K]3 years ago
4 0

Answer:

It is not a function.  

Step-by-step explanation:

A function is a relation in which each input x has only one output y.

One visual way to tell the difference is to plot the relation and use the vertical line test.

If a vertical line for a  given value of x passes through more than one point, the relation is not a function.

We see in the diagram that the line x = -3  includes (-3,0) and (-3,4), so the relation is not a function.

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Simplify the expression. Write the answer using scientific notation. (4 × 108)2
Tom [10]

Answer:

864

Step-by-step explanation:

(4)(108)(2)

=(432)(2)

=864

3 0
3 years ago
A particular state has elected both a governor and a senator. Let A be the event that a randomly selected voter has a favorable
Elodia [21]

Answer:

Step-by-step explanation:

Given that A be the event that a randomly selected voter has a favorable view of a certain party’s senatorial candidate, and let B be the corresponding event for that party’s gubernatorial candidate.

Suppose that

P(A′) = .44, P(B′) = .57, and P(A ⋃ B) = .68

From the above we can find out

P(A) = 1-0.44 = 0.56

P(B) = 1-0.57 = 0.43

P(AUB) = 0.68 =

0.56+0.43-P(A\bigcap B)\\P(A\bigcap B)=0.30

a) the probability that a randomly selected voter has a favorable view of both candidates=P(AB) = 0.30

b) the probability that a randomly selected voter has a favorable view of exactly one of these candidates

= P(A)-P(AB)+P(B)-P(AB)

=0.99-0.30-0.30\\=0.39

c) the probability that a randomly selected voter has an unfavorable view of at least one of these candidates

=P(A'UB') = P(AB)'

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3 0
3 years ago
Tickets for a school play sold for $7.50 for each adult and $3.00 for each child. The total receipts for 118 tickets totaled $69
NeX [460]
X= number of adult tickets
y=number of child tickets.
we can suggest this system of equations: 
x+y=118                 ⇒x=118-y
7.5x+3y=696

we can solve this system of equations by substitution method:
7.5(118-y)+3y=696
885-7.5y+3y=696
-4.5y=-189
y=-189/-4.5
y=42

x=118-y
x=118-42
x=76

Answer: the number of adult tickets sold was 76. 
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3 years ago
Help! Will give crown to the most helping
kolbaska11 [484]
The first one seems more reasonable
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Novay_Z [31]

Answer:

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4 0
2 years ago
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