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igor_vitrenko [27]
3 years ago
10

(See Attachment)

Mathematics
1 answer:
vesna_86 [32]3 years ago
8 0
The solution would be the coordinates of (3a,a).
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one day on flu season 1/3 of students got sick and only 24 were left at school how many students are there in all
ohaa [14]
If we assume that all students who were not sick came then
3/3-1/2=2/3 left

24 were at school
24=2/3 of all
times both sides by 3/2
72/2=all
36=all

there are 36 students
3 0
3 years ago
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The dimensions of a rectangle are 2x – 5 and 3x + 3. Which expression
Ulleksa [173]

Answer: 2x - 5

Step-by-step explanation: 2x - 5 does not have anything in common, so therefore it can not be simplified. Then 3x - 3 can be divided by 3 because they have that in common. It can’t be 3x - 3 because it still contains one step left to be in its most simplified form.

6 0
3 years ago
3/4 / 3/5 divided. write your answer in simplest form or as a mixed number in simplest
Gnoma [55]

Answer: 5/4

Step-by-step explanation:

do the keep change flip method

then it will be 3/4*5/3 which then equals 15/12 after that you would divide by 3 cause it is the only number that would go in evenly then the answer will be 5/4 in the simplest form

6 0
3 years ago
Please answer this, I'd appreciate it<br> Simplify too
mezya [45]

Answer:

A.) w² + 3w in²

B.) 28 in²

Step-by-step explanation:

A.)

Let w = width and l = length.

    The area of a rectangle can be written as length · width (base · height). The problem informs us that the length of the rectangle is 3 inches greater than the width. Therefore, l can also be written as w + 3. We can use this to form a polynomial that represents the area of the rectangle.

A(rectangle) = lw = (w + 3) · w = w² + 3w

B.)

Use the polynomial we previously found to find the area.

A(rectangle) = (4)² + 3(4) = 16 + 12 = 28 in²

Model:

7 0
3 years ago
Given the system of equations, what is the solution?<br><br> x + 3y = 5<br> x - 3y = -1
mr_godi [17]
\begin{cases}x+3y=5\\x-3y=-1 \end{cases}\\---------(+)\\\\x+x+3y-3y=5+(-1)\\\\2x=4\qquad|:2\\\\\boxed{x=2}\\\\\\\\x+3y=5\\\\2+3y=5\qquad|-2\\\\2+3y-2=5-2\\\\3y=3\qquad|:3\\\\\boxed{y=1}

The solution is (2; 1)
3 0
3 years ago
Read 2 more answers
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