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2 years ago

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A 180 B360 C90 D720 Please help me

1 answer:

vaieri [72.5K]2 years ago

8 0

Answer:

360 is the answer .........

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For each expression, write an equivalent expression that only uses addition a. 20 - 9 + 8 -7 b. 4x - 7y - 5z + 6 c. -3x - 8y - 4

Genrish500 [490]

Answer:

a. =11+ 1

b. =4x+ (-7y) + (-5z) +6

c. (-3x) + (-8y) +(-4)+(-8/7z)

Step-by-step explanation:

a. 20 - 9 + 8 -7

=11+ 1 ( this is obtained by solving)

b. 4x - 7y - 5z + 6

=4x+ (-7y) + (-5z) +6

We multiply the negative sign with the positive sign to get a minus so the answer remains the same and the expression is written as an addition sum.

c. -3x - 8y - 4 - 8/7z

-[ 3x+8y+4+8/7z]

or

(-3x) + (-8y) +(-4) +(-8/7z)

The minus sign is taken as common leaving the expression with the plus only.

It can be written in the same manner as above, adding the negative terms so that the expression is written as a sum.

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2 years ago

There are 2,920 seats in an auditorium. the audition has 20 sections with the same number of seats in each section. how many sea

OverLord2011 [107]

143 seats
because 2920 seats/20 sections=143 seats in each section

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3 years ago

Autumn buys eggs and apples at the store.

soldier1979 [14.2K]

Answer:

$\frac{(5.76-34.14)}{6}$

Step-by-step explanation:

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1 year ago

Two cakes were cut into 8 slices iate 1/8 of the carrot cake . Iate 1/2 of the carrot cake .Me ate 1 slice of each. I ate three

FromTheMoon [43]

Answer:

There are 6 slices left.

Step-by-step explanation:

The remaining slices are:

Carrot Cake

$x = \left(\frac{8}{8} -\frac{1}{8} -\frac{4}{8} -\frac{1}{8} \right)\cdot 8$

$x = 2$

Chocolate Cake

$y = \left(\frac{8}{8} - \frac{1}{8} - \frac{3}{8} \right)\cdot 8$

$y = 4$

There are 6 slices left.

7 0

2 years ago

et f(x) = x + |2x − 3|. Find all solutions to the equation f(x) = 12. (Enter your answers as a comma-separated list. If an answe

Alinara [238K]

Answer:

1. {5,-9}

2.{4}

3.{9/2}

Step-by-step explanation:

The equation $f(x)=x+\lvert 2x-3 \rvert=12$ can be solved as follows:

$x+\lvert 2x-3 \rvert =12\,\,\,\text{(given equation)}$

$\lvert 2x-3 \rvert =12-x$

$2x-3=12-x\,\,\text{or}\,\,2x-3=-(12-x)$

$3x=15\,\,\text{or}\,\,\x=-9$

Then, the solutions of the equation are $x=5, x=-9$ .

Now, if $g(x)=5x-3+\lvert x+4\rvert$ , we can solve the equation $g(a)=4a+9$ as follows:

$5a-3+\lvert a+4 \rvert =4a+9$

$\lvert a+4\rvert =4a+9-5a+3$

$a+4 =-a+12\,\,\text{or}\,\,a+4=-(-a+12)$

$2a=8\,\,\text{or}\,\,4=12$

So, the unique solution of this last equation is $a=4$

The last equation is $h(x-1)=x-3$ , where $h(x)=\lvert x \rvert -2x+5.$ . To solve this equation we can proceed as follows:

$h(x-1)=x-3$

$\lvert x-1\rvert -2(x-1)+5=x-3$

$\lvert x-1 \rvert -2x+2+5=x-3$

$\lvert x-1\rvert =3x-10$

$x-1=3x-10\,\,\text{or}\,\,x-1=-(3x-10)$

$-2x=-9\,\,\text{or}\,\,4x=11$

$x=9/2\,\,\text{or}\,\,x=11/4$

But, x=11/4 is not a solution of this equation. So the unique solution is x=9/2.

8 0

2 years ago