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2 years ago

Adison earned $25 mowing her neighbors lawn. Then she loaned her friend $18 and her granfmother gave her $50 for her birthday. S

he now has $86. How much money did she start with

Mathematics

1 answer:

Soloha48 [4]2 years ago

7 0

$86 = x + 25 - 18 + 50 \\ x = 29$

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2 years ago

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2 years ago

an old building has 48 big windows the building has 12 small windows thare are 9 broken windows how many windows are not broken

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Answer:

Step-by-step explanation:

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2 years ago

Read 2 more answers

For each situation, state the null and alternative hypotheses: (Type "mu" for the symbol μ , e.g. mu > 1 for the mean is grea

Nitella [24]

Answer:

Part (A) $H_0:\mu=2.5$ and $H_a:\mu\neq2.5$

Part (B) $H_0:\mu=16.35$ and $H_a:\mu$

Step-by-step explanation:

Consider the provided information.

Null hypothesis refers the population parameter is equal to the claimed value.

If there is no statistical significance in the test then it is know as the null which is denoted by $H_0$ , otherwise it is known as alternative hypothesis denoted by $H_a$ .

Part (A): The diameter of a spindle in a small motor is supposed to be 2.5 millimeters (mm) if the spindle is either too small or too large, the motor will not work properly.

Thus, the required null and alternative hypothesis are:

$H_0:\mu=2.5$ and $H_a:\mu\neq2.5$

Part (B) The nationwide average price of a certain brand of laundry detergent is $16.35 and Harry thinks that prices in Caldwell are lower than the rest of the country.

Thus, the required null and alternative hypothesis are:

$H_0:\mu=16.35$ and $H_a:\mu$

6 0

2 years ago

Find the area of the triangle<br> 1. C=110 degrees, a=6, b=10<br> 2. B=130 degrees, a=92, c=30

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$1.\ \ \ |\angle \ ACB|=110^0\\\\.\ \ \ \ \ a=|BC|=6\ [u]\ \ \ and\ \ \ b=|AC|=10\ [u]\\\\Area= \frac{1}{2} \cdot |AC|\cdot |BC|\cdot sin(|\angle \ ACB|)\\\\Area= \frac{1}{2} \cdot 6\cdot 10\cdot sin110^0=30\cdot sin (180^0-70^0)=\\\\.\ \ \ \ \ \ =30\cdot sin70^0\approx30\cdot 0.9397=28.191\ [u^2]\\\\$

$2.\ \ \ |\angle \ ABC|=130^0\\\\.\ \ \ \ \ a=|BC|=92\ [u]\ \ \ and\ \ \ c=|AB|=30\ [u]\\\\Area= \frac{1}{2} \cdot |AB|\cdot |BC|\cdot sin(|\angle \ ABC|)\\\\Area= \frac{1}{2} \cdot 30\cdot 92\cdot sin130^0=1380\cdot sin (180^0-50^0)=\\\\.\ \ \ \ \ \ =1380\cdot sin50^0\approx1380\cdot 0.7660=1057.08\ [u^2]\\\\$

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2 years ago