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3 years ago

11

How would I find x to 4x+10=6x-2

2 answers:

Elena L [17]3 years ago

8 0

4x+10=6x-2
Combine the like terms “4x” and “6x”
So, it’s “4x-6x=-2-10”
-2x=-12
Make it positive (when two negatives, it’s the same as positive in an equation)
x=6

mixer [17]3 years ago

7 0

Answer:

6

Step-by-step explanation:

yoy would subtract the 6x by the 4x getting -2x+10= -2. then you would subtract the 10 from the -2 and get -2x=-12. last divide the -2 by -12 giving you positive 6

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3 years ago

the first group of students consists of 10 and their average age was 13 years old the next group consisted of 30 students and th

Kazeer [188]

Answer: The average was 9 years old find the average age of both groups is 10 years old.

Step-by-step explanation:

Formula foe average : $\text{Average} =\dfrac{\text{Sum of all observations}}{\text{Number of observations}}$

Given : The first group of students consists of 10 and their average age was 13 years old.

i.e. $13=\dfrac{\text{Sum of ages of students of first group}}{10}\\\\\Rightarrow\ \text{Sum of ages of students of first group}=13\times10=130$ (1)

The next group consisted of 30 students and their average was 9 years old.

i.e. $9=\dfrac{\text{Sum of ages of students of next group}}{30}\\\\\Rightarrow\ \text{Sum of ages of students of nextgroup}=9\times30=270$ (2)

Then from (1) and (2) , the sum of both groups (first group and next group )students = 130+270 =400

Combined students of both groups (first and next group )= 10+30=40

Now , the average of both groups = $\dfrac{\text{Sum of combined students}}{\text{combined students}}$

$=\dfrac{400}{40}=10$

Hence, the average was 9 years old find the average age of both groups is 10 years old.

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