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jeka57 [31]
3 years ago
13

What's the largest 3-digit base 14 integer?

Mathematics
1 answer:
Mars2501 [29]3 years ago
3 0
Base 10 has the ten digits: {0, 1, 2, 3, 4, 5, 6,7, 8, 9}

Base 11 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A} where A is treated as a single digit number

Base 12 has the digits {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B}

Base 13 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C}

Base 14 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D}

The digit D is the largest single digit of that last set. So the largest 3-digit base 14 integer is DDD which is the final answer

Note: It is similar to how 999 is the largest 3-digit base 10 integer
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frank and his family drove 6 hours every day during a road trip which graph best represents y the total of hours driven in x day
Marta_Voda [28]

Answer:Where is the graph?

Step-by-step explanation:

6 0
3 years ago
A rental truck cost $48 plus $0.40 per mile.
Natalija [7]
(a) If we let x be the number of miles and y be the total cost, the equation for relating the number of miles and the total cost would be,
                                y = 0.4x + 48

(b) If the rental cost is 60,
                               60 = 0.4x + 48
The value of x from the equation is 30.

(c) You may prepare the table of values by allowing x be any number and then solve for y until we arrive with an answer for y being equal to 60. 
3 0
3 years ago
PLESE HELPPP!!!!!!!!!!!!!!!!
zzz [600]

Answer:

B. \frac{6}{2x^{2}  - 5x}

Step-by-step explanation:

The product of the ratioal expressions given above can be found as follows:

= \frac{2}{x} * \frac{3}{2x - 5}

Multiply the denominators together, and the numerators together, separately to get a single expression

\frac{2(3)}{x(2x - 5)}

= \frac{6}{x(2x) - x(5)}

= \frac{6}{2x^{2}  - 5x}

The product of the expression \ = \frac{2}{x}*\frac{3}{2x - 5} = \frac{6}{2x^{2}  - 5x}

The answer is B.

8 0
3 years ago
My Notes A large manufacturing plant uses lightbulbs with lifetimes that are normally distributed with a mean of 1600 hours and
Evgen [1.6K]

Answer:

The bulbs should be replaced each 1436.9 hours.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 1600, \sigma = 70

How often should the bulbs be replaced so that no more than 1% burn out between replacement periods?

This is the first percentile of hours. So it is X when Z has a pvalue of 0.01.

So it is X when Z = -2.33.

Z = \frac{X - \mu}{\sigma}

-2.33 = \frac{X - 1600}{70}

X - 1600 = -2.33*70

X = 1436.9

The bulbs should be replaced each 1436.9 hours.

6 0
3 years ago
What is the next number on 12,24,72,288 the pattern
Julli [10]
They are all multiples of 12. 12x1, 12x2, 12x6, 12x24.
8 0
3 years ago
Read 2 more answers
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