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jeka57 [31]
3 years ago
13

What's the largest 3-digit base 14 integer?

Mathematics
1 answer:
Mars2501 [29]3 years ago
3 0
Base 10 has the ten digits: {0, 1, 2, 3, 4, 5, 6,7, 8, 9}

Base 11 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A} where A is treated as a single digit number

Base 12 has the digits {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B}

Base 13 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C}

Base 14 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D}

The digit D is the largest single digit of that last set. So the largest 3-digit base 14 integer is DDD which is the final answer

Note: It is similar to how 999 is the largest 3-digit base 10 integer
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First of all, I'm going to assume that we have a concave down parabola, because the stream of water is subjected to gravity.

If we need the vertex to be at x=4, the equation will contain a (x-4)^2 term.

If we start with y=-(x-4)^2 we have a parabola, concave down, with vertex at x=4 and a maximum of 0.

So, if we add 7, we will translate the function vertically up 7 units, so that the new maximum will be (4, 7)

We have

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Now we only have to fix the fact that this parabola doesn't land at (8,0), because our parabola is too "narrow". We can work on that by multiplying the squared parenthesis by a certain coefficient: we want

y = a(x-4)^2+7

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Plugging these values gets us

0 = a(8-4)^2+7 \iff 16a+7=0 \iff a = -\dfrac{7}{16}

As you can see in the attached figure, the parabola we get satisfies all the requests.

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3 years ago
Riley brought cupcakes to a party. by the end of the party 5/6 of the cupcakes were gone. what fraction of the cupcakes were lef
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1/6

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this seems too simple but...

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Answer:. .

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