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Varvara68 [4.7K]
3 years ago
8

Can you do Nmb 1,2,3

Mathematics
1 answer:
vovikov84 [41]3 years ago
3 0
QUESTION 1:

2 -3 0.3 2/3 -1/4

For a start, everything to the power of 0 equals 1, so you can write 1 for everything in the top row.

Then, everything to the power of 1 equals itself, so for the 2nd row, write:
2, -3, 0.3, 2/3, -1/4

The rest of it is here:

2 ^ 2 = 4
2 ^3 = 8
2 ^4 = 16
2 ^5 = 32

-3 ^ 2 = -9
-3 ^ 3 = -27
-3 ^ 4 = -81
-3 ^ 5 = -243

0.3 ^ 2 = 0.09
0.3 ^ 3 = 0.027
0.3 ^ 4 = 0.0081
0.3 ^ 5 = 0.00243

2/3 ^ 2 = 0.22
2/3 ^ 3 = 0.074
2/3 ^ 4 = 0.025
2/3 ^ 5 = 0.008

(-1/4) ^ 2 = 0.0625
(-1/4) ^ 3 = (-0.016)
(-1/4) ^ 4 = 0.004
(-1/4) ^ 5 = (-0.00098)

Unfortunately I currently don't have time to help you on Questions 2 or 3, but I hope this helps! :)
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Help me!!11111111111111
zheka24 [161]
How to solve:

( x , y )

Plug the values in to the equation and solve

-3x+5y=2x+3y

(2,4) plugged in would be

-3(2)+5(4)=2(2)+3(4)

All you have to do is solve this and if the two sides are not equal(like 4=20), then it is not a solution. Just plug in (3,3) next.

Hope this helped!!!
3 0
3 years ago
Find the slope of the parametric curve xequalsnegative 4 t cubed plus 8​, yequals5 t squared​, for negative infinity less than t
Licemer1 [7]
Take a picture so I can do the problem
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3 years ago
The probability of passing the math class of Professor Jones is 64%, the probability of passing Professor Smith's physics class
alexgriva [62]

Answer:

The probability of using one or the other is 36%

Step-by-step explanation:

For solving this problem it is easy if we see it in a ven diagram, for this first we are going to name the initial conditions with some variables:

Probability of passing Professor Jones math class = 64% =0,64

P(J) = 0.64

Probabiliry of passing Professor Smith's physics class = 32% =0.32

P(S) = 0.32

Probability of passing both is = 30% = 0.30

P(JnS) = 0.30 (Is is an intersection so it is in the middle of the ven diagram

We need to know which is the probability of pasing one or the other for this we need to take out the probability of passing both for this we have to add the probability of passing  Professor Jones math class with the probabiliry of passing Professor Smith's physics class and substract the probability of passing both for each one:

P(JuS) = (P(J) - P(JnS)) + (P(S) - P(JnS)) = (0.64 - 0.30) + (0.32 - 0.30) = 0.34 + 0.02 = 0.36 = 36%

If you check the ven diagram you can see that if we add all what is in red we will have the probability of passing Professor Jones math class and if we add all what is in blue we wiill have the probability of passing Professor Smith's physics class, and if we add just what is in each corner we will get the same value that is the probabilty of passsing one or the other.

5 0
3 years ago
Jeremy is taking a photography class, but he doesn't own a camera. The class organizers will rent him a camera for $6 per day. J
Mazyrski [523]
Solving the given inequality for d, we get...

6d + 15 < 50
6d + 15-15 < 50-15 <<-- subtract 15 from both sides
6d < 35
6d/6 < 35/6 <<--- divide both sides by 6
d < 5.83

Which means that d can be any of the values in this set: {0, 1, 2, 3, 4, 5}

The smallest d can be is 0. In this scenario, Jeremy pays the $15 registration but doesn't rent the camera at all
The largest d can be is 5. In this scenario, Jeremy rents the camera for 5 days
Any larger value of d is not allowed as it would make the total cost go over $50
Notice how I'm rounding down regardless how close 5.83 is to 6

8 0
3 years ago
Read 2 more answers
Simply 20-3[4(z+1)-6(z-2)]
creativ13 [48]

Answer:

The answer is 6z-28

Step-by-step explanation:

20 - 3[4(z+1) - 6(z-2)]

= 20 - 3(4z+4-6z+12)

= 20 - 3(16 - 2z)

= 20 - 48 + 6z

= 6z - 28

8 0
3 years ago
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