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LUCKY_DIMON [66]
3 years ago
14

What is the point of intersection when the system of equations below is graphed on the coordinate plane? (1, –3) (–1, 3) (1, 3)

(–1, –3)
Mathematics
2 answers:
Ainat [17]3 years ago
5 0

( - 1 - 3)
it's lower
Lubov Fominskaja [6]3 years ago
5 0

Answer:(-1,3)

Step-by-step explanation:

Correct answer

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2x-3y=-1, 2x+y=11solve the system equation
agasfer [191]

Answer:

x = 4, y = 3

Step-by-step explanation:

   2x - 3y = -1

-   <u>2x + y =  11</u>

         -4y = -12

            y = 3

solve for 'x':

2x -3(3) = -1

2x - 9 = -1

2x = 8

x = 4

4 0
3 years ago
If you choose an answer to this question at random, what is the chance you will be correct?
Daniel [21]
I believe the answer is B right??? and why are there two 25% ? 
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3 years ago
Helppppp idk how tu du dis
Arlecino [84]
This expression simplified is 9n^4+8n^3+4
4 0
3 years ago
Read 2 more answers
Find the slope of the line<br>A -3<br>B 3 <br>C -2 <br>D 2​
VikaD [51]
Y=-2x-10
So it would be -2
7 0
3 years ago
HELP IM FAILING MATH OOOOFFFF
meriva

The point-slope form:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (-4,\ -1) and \left(\dfrac{1}{2},\ 3\right).

Substitute:

m=\dfrac{3-(-1)}{\frac{1}{2}-(-4)}=\dfrac{4}{4\frac{1}{2}}=\dfrac{4}{\frac{9}{2}}=4\cdot\dfrac{2}{9}=\dfrac{8}{9}\\\\y-(-1)=\dfrac{8}{9}(x-(-4))\\\\y+1=\dfrac{8}{9}(x+4)

The standard form: Ax + By = C

y+1=\dfrac{8}{9}(x+4)\qquad\text{multiply both sides by 9}\\\\9y+9=8(x+4)\qquad\text{use distributive property}\\\\9y+9=8x+32\qquad\text{subtract 9 from both sides}\\\\9y=8x+23\qquad\text{subtract 8x from both sides}\\\\-8x+9y=23\qquad\text{change the signs}\\\\\boxed{8x-9y=23}

4 0
4 years ago
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