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Mars2501 [29]
3 years ago
11

a certain forest covers an area of 3100 km^2. suppose that each year this area decreases by 8.25%. what will the area be after 1

5 years? round to the nearest square kilometer.
Mathematics
1 answer:
IrinaK [193]3 years ago
8 0
A decrease of 8.25% means the reduction factor is 100-8.25=91.75%=0.9175.
The shrinkage over 15 years is 0.9175¹⁵=0.27485 approx, so the size of the forest will be 3100×0.27485=852 sq km approx.
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Triangle Similarity What is the value of x?
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To solve this you can make a proportion where the matching sides will correspond to each other. It should look something like this:

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4 years ago
A population has a mean muequals160 and a standard deviation sigmaequals20. Find the mean and standard deviation of the sampling
hoa [83]

Answer:

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Standard deviation 2.63

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 160, \sigma = 20

Find the mean and standard deviation of the sampling distribution of sample means with sample size n = 58.

Mean 160

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