Ask question

Ask question

All categories

2 years ago

5

Triangles A and B are similar. If the slope of y is -2, what is the slope of x?

2 answers:

kati45 [8]2 years ago

7 0

Slope x would be -1 because if you enlarge the triangle on the right to make it even with the triangle on the left, you will get the same answer. I hope this helps you out.

hodyreva [135]2 years ago

6 0

You basically dilate the slope of y to the slope of x by the same scale factor at which all the sides of the triangles are dilated or increased/decreased by.

You might be interested in

Find the slope of the line through the given points.<br> (8,0) and (10, 10)

postnew [5]

Slope (y2-y1)/(x2-x1)
(10-0)/(10-8) = 10/2 = 5
The slope is 5

6 0

2 years ago

Mariah collects 3 spiders each spider has eight legs.Brian gives her 1more spider. how many legs do Mariah's spiders have altoge

kompoz [17]

Tem 32 pernas de aranha

6 0

2 years ago

arlik [135]

Given:

In a right angle triangle θ is an acute angle and $\tan\theta =\dfrac{3}{5}$ .

To find:

The value of $\cos \theta$ .

Solution:

In a right angle triangle,

$\tan \theta=\dfrac{Perpendicular}{Base}$

We have,

$\tan\theta =\dfrac{3}{5}$

It means the ratio of perpendicular to base is 3:5. Let 3x be the perpendicular and 5x be the base.

By using Pythagoras theorem,

$Hypotenuse=\sqrt{Perpendicular^2+base^2}$

$Hypotenuse=\sqrt{(3x)^2+(5x)^2}$

$Hypotenuse=\sqrt{9x^2+25x^2}$

$Hypotenuse=\sqrt{34x^2}$

$Hypotenuse=x\sqrt{34}$

In a right angle triangle,

$\cos \theta=\dfrac{Base}{Hypotenuse}$

$\cos \theta=\dfrac{5x}{x\sqrt{34}}$

$\cos \theta=\dfrac{5}{\sqrt{34}}$

Therefore, the value of $\cos \theta$ is $\dfrac{5}{\sqrt{34}}$ .

8 0

2 years ago

The thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters. (a) Determine the

maxonik [38]

Answer:

a) 0.5 = 50% of flanges exceed 1 millimeter.

b) A thickness of 0.96 millimeters is exceeded by 90% of the flanges

Step-by-step explanation:

A distribution is called uniform if each outcome has the same probability of happening.

The uniform distributon has two bounds, a and b, and the probability of finding a value higher than x is given by:

$P(X > x) = \frac{b - x}{b - a}$

The thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters.

This means that $a = 0.95, b = 1.05$

(a) Determine the proportion of flanges that exceeds 1.00 millimeters.

$P(X > 1) = \frac{1.05 - 1}{1.05 - 0.95} = \frac{0.05}{0.1} = 0.5$

0.5 = 50% of flanges exceed 1 millimeter.

(b) What thickness is exceeded by 90% of the flanges?

This is x for which:

$P(X > x) = 0.9$

So

$\frac{1.05 - x}{1.05 - 0.95} = 0.9$

$1.05 - x = 0.9*0.1$

$x = 1.05 - 0.9*0.1$

$x = 0.96$

A thickness of 0.96 millimeters is exceeded by 90% of the flanges

4 0

2 years ago

I like you cookie want go out what me :]

Gelneren [198K]

Answer: lol wut

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers