Answer:
Step-by-step explanation:
2(x + 15)⁰ + (3x + 20)⁰=180⁰
2x + 30⁰ + 3x + 20⁰=180⁰
2x + 3x + 30⁰ + 20⁰=180⁰
5x + 50⁰ - 50⁰=180⁰-50⁰
5x=130⁰
5x/5=130⁰/5
x=26⁰
Let x be the resistance of the wire with the larger diameter.
x = (0.456 x (0.01)^2)/(0.0401)^2 = 0.0284 ohms
The answer is 0.0284 ohms.
The 2+3=45 confuses me but the answer is 126 for 9+4. the reason for this is because (9*9)+(9*4)=126.
Xy = 6
x = 2
2y = 6
y = 6÷2
y = 3
x + y = (2) + (3) = 5
Answer:
![\dfrac{\$1000+\$20x}{x} \leq \$25](https://tex.z-dn.net/?f=%5Cdfrac%7B%5C%241000%2B%5C%2420x%7D%7Bx%7D%20%5Cleq%20%5C%2425)
Minimum 200 people other than the 2 charity representatives.
Step-by-step explanation:
Given that:
The venue can hold a maximum of 500 people.
Cost of venue = $1000
Per person cost for food = $20
Two charity representatives get to attend the dinner for free.
To find:
The inequality and to determine how many people must come to keep costs at most $25.
Solution:
Let the number of people attending the dinner = ![x](https://tex.z-dn.net/?f=x)
Cost of food for
people = ![\$20x](https://tex.z-dn.net/?f=%5C%2420x)
Total cost = $1000 + ![\$20x](https://tex.z-dn.net/?f=%5C%2420x)
Cost per person = Total cost divided by Number of people attending the dinner.
As per question statement:
![\dfrac{\$1000+\$20x}{x} \leq \$25\\\Rightarrow 1000+20x\leq25x\\\Rightarrow 1000 \leq 5x\\\Rightarrow x\geq 200](https://tex.z-dn.net/?f=%5Cdfrac%7B%5C%241000%2B%5C%2420x%7D%7Bx%7D%20%5Cleq%20%5C%2425%5C%5C%5CRightarrow%201000%2B20x%5Cleq25x%5C%5C%5CRightarrow%201000%20%5Cleq%205x%5C%5C%5CRightarrow%20x%5Cgeq%20200)
Therefore, the answer is:
Minimum 200 people other than the 2 charity representatives should attend the dinner.