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enot [183]
3 years ago
10

Help me ples!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
bearhunter [10]3 years ago
6 0
It would be subtraction I think
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A soup can has a 3 and one eighth in diameter and is 5 in tall. What is the area of the paper that will be used to make the labe
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Answer: 49.09 cm2

Step-by-step explanation:

Hi, to answer this question we have to apply the next formulas:

Circumference of a circle = π x diameter = 3.14159x 3 1/8 = 9.81746 in

The circumference of the can is equal to the length of the rectangular label:

Surface area (S)= circumference(length) x height  

Replacing with the values given:

S = 9.81746 x 5 = 49.09 cm2

Feel free to ask for more if needed or if you did not understand something.

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3 years ago
Point M is between points N and K. Along the same segment, pointL is between points M and K. If NM = 110 + 4x, ML = x + 103,LK =
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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2 years ago
Determine whether each integral is convergent or divergent. If it is convergent evaluate it. (a) integral from 1^(infinity) e^(-
AVprozaik [17]

Answer:

a) So, this integral is convergent.

b) So, this integral is divergent.

c) So, this integral is divergent.

Step-by-step explanation:

We calculate the next integrals:

a)

\int_1^{\infty} e^{-2x} dx=\left[-\frac{e^{-2x}}{2}\right]_1^{\infty}\\\\\int_1^{\infty} e^{-2x} dx=-\frac{e^{-\infty}}{2}+\frac{e^{-2}}{2}\\\\\int_1^{\infty} e^{-2x} dx=\frac{e^{-2}}{2}\\

So, this integral is convergent.

b)

\int_1^{2}\frac{dz}{(z-1)^2}=\left[-\frac{1}{z-1}\right]_1^2\\\\\int_1^{2}\frac{dz}{(z-1)^2}=-\frac{1}{1-1}+\frac{1}{2-1}\\\\\int_1^{2}\frac{dz}{(z-1)^2}=-\infty\\

So, this integral is divergent.

c)

\int_1^{\infty} \frac{dx}{\sqrt{x}}=\left[2\sqrt{x}\right]_1^{\infty}\\\\\int_1^{\infty} \frac{dx}{\sqrt{x}}=2\sqrt{\infty}-2\sqrt{1}\\\\\int_1^{\infty} \frac{dx}{\sqrt{x}}=\infty\\

So, this integral is divergent.

4 0
3 years ago
») Noah finds 14 caterpillars and puts them in 2 cages.
Allisa [31]

Answer:

7 Caterpillars

Step-by-step explanation:

14/2

7 0
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