You would be concluding that <span>the populations from which our samples come are different. I hope this helps.</span>
ED = x - 5 <em>given</em>
DG = 4x - 38 <em>given</em>
ED = DG <em>definition of midpoint</em>
x - 5 = 4x - 38 <em>substitution</em>
-5 = 3x - 38 <em>subtraction property of equality (subtracted x from both sides)</em>
33 = 3x <em>addition property of equality (added 38 to both sides)</em>
11 = x <em>division property of equality (divided 3 from both sides)</em>
ED = x - 5 → ED = 11 - 5 → ED = 6 <em>substitution</em>
since ED = DG, then DG = 6 <em>transitive property</em>
ED + DG = EG <em>segment addition property</em>
6 + 6 = EG <em>substitution</em>
12 = EG <em>simplified like terms</em>
Answer: 12
Answer:
42 ounces of yellow paint.
Step-by-step explanation:
- To make three cups of dark orange, you just need to remember that to make one cup you need: 7 ounces of red paint and 1 ounce of yellow paint. Then, to make three cups, we just have to multiply these proportions by three,which means 7x3 ounces of red paint =21 ounces of red paint, plus 3x1 ounces of yellow paint =3 ounces of yellow paint. Then we need 21 ounces of red paint and 3 of yellow paint to make three cups of dark orange.
- To make one cup of light orange, we need 13 ounces of yellow paint, and 3 ounces of red paint. Then, to make three cups, we just multiply this proportion by 3, as follows: 13x3 ounces of yellow paint = 39; and 3x3 ounces of red paint =9. Then we need 9 ounces of red paint and 39 of yellow paint to make three cups of light orange.
- Adding up the amount of ounces we need to make dark orange and light orange, we get a total amount of 21+9=30 ounces of red paint and 3+39=42 ounces of yellow paint to make three cups of light orange and three cups of dark orange.
Answer:
i don't have and idea
Step-by-step explanation:
The answer is C. 89 in^2
This is found by (1/2(

))+70
r in this equation stands for radius which is half the diameter. Sice the diameter equals 7, the radius equals 3.5
You have to solve this by putting it into a calculator since you can't really solve for an equation with pi in it otherwise.
Hope this helps!