Answer:
Given the domain, the range for 3x-y = 3 is {-9, 6, 9}
Step-by-step explanation:
First you have to put the relation in terms of y ⇒ 3x - y = 3⇒ 3x -3 = y
⇒ y = 3x - 3.
Then you replace the values indicated by the domain to find their "y" values (the ones that constitute the range).
f(-2) = -9
f(2) = 6
f(4) = 9.
Finally, the range for the given domain is {-9, 6, 9}
Answer:
24/25
Step-by-step explanation:
COS = adjacent/hypotenuse
Answer:
- north and south sides are 38 8/9 ft long
- east and west sides are 17.5 ft long
Step-by-step explanation:
<u>Short answer</u>: area is maximized when half the cost is spent in each of the orthogonal directions. This means the east and west sides will total $350 at $20 per foot, so will be 17.5 feet. The north and south sides will total $350 at $9 per foot, so will be 38 8/9 feet.
The dimensions that maximize the area are 17.5 ft in the north-south direction by 38 8/9 ft in the east-west direction.
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<u>Long answer</u>: If x represents the length of the north and south sides, and y represents the length of the east and west sides, then the total cost is ...
10y +10y +2x +7x = 700
9x +20y = 700
y = (700 -9x)/20
We want to maximize the area:
A = xy = x(700 -9x)/20
We can do this by differentiating and setting the derivative to zero:
dA/dx = 700/20 -9x/10 = 0
350 -9x = 0 . . . . multiply by 10
x = 350/9 = 38 8/9
y = (700 -9(350/9))/20 = 350/20 = 17.5
The north and south sides are 38 8/9 ft long; the east and west sides are 17.5 ft long to maximize the area for the given cost.
Answer:
Step-by-step explanation:
B'(0,2),C'(3,4),z'(4,3),X'(4,1)
