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3 years ago

Please someone factor 8 + 16 !!!!!

Mathematics

1 answer:

Effectus [21]3 years ago

7 0

Answer:

8,4,2,1

Step-by-step explanation:

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Plz explain step by step

kirill115 [55]

Step-by-step explanation:

a=20⁰ vertically opposite angles are equal

b=160⁰ sum of angles on a straight line add up to 180⁰

(180⁰-20⁰=60⁰)

c=125⁰ sum of angles on a straight line add up to 180⁰

(180⁰-35⁰-20⁰=125⁰)

8 0

2 years ago

What type of number is

eimsori [14]

Answer:

A) rational number

Step-by-step explanation:

56 is a rational number because it can be expressed as the quotient of two integers like 56 ÷ 1.

6 0

3 years ago

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Which expressions is equivalent to (x+2)(3x-3)

max2010maxim [7]

Answer:

Step-by-step explanation:

(x+2)(3x-3)

= 3x^2 -3x + 6x - 6

= 3x^2 + 3x - 6

6 0

3 years ago

An urn contains 5 white and 10 black balls. A fair die is rolled and that number of balls is randomly chosen from the urn. What

galina1969 [7]

Answer:

Part A:

The probability that all of the balls selected are white:

$P(A)=\frac{1}{6}(\frac{1}{3}+\frac{2}{21}+\frac{2}{91}+\frac{1}{273}+\frac{1}{3003}+0)\\ P(A)=\frac{5}{66}=0.075757576$

Part B:

The conditional probability that the die landed on 3 if all the balls selected are white:

$P(D_3|A)=\frac{\frac{2}{91}*\frac{1}{6}}{\frac{5}{66} } \\P(D_3|A)=\frac{22}{455}=0.0483516$

Step-by-step explanation:

A is the event all balls are white.

D_i is the dice outcome.

Sine the die is fair:

$P(D_i)=\frac{1}{6}$ for i∈{1,2,3,4,5,6}

In case of 10 black and 5 white balls:

$P(A|D_1)=\frac{5_{C}_1}{15_{C}_1} =\frac{5}{15}=\frac{1}{3}$

$P(A|D_2)=\frac{5_{C}_2}{15_{C}_2} =\frac{10}{105}=\frac{2}{21}$

$P(A|D_3)=\frac{5_{C}_3}{15_{C}_3} =\frac{10}{455}=\frac{2}{91}$

$P(A|D_4)=\frac{5_{C}_4}{15_{C}_4} =\frac{5}{1365}=\frac{1}{273}$

$P(A|D_5)=\frac{5_{C}_5}{15_{C}_5} =\frac{1}{3003}=\frac{1}{3003}$

$P(A|D_6)=\frac{5_{C}_6}{15_{C}_6} =0$

Part A:

The probability that all of the balls selected are white:

$P(A)=\sum^6_{i=1} P(A|D_i)P(D_i)$

$P(A)=\frac{1}{6}(\frac{1}{3}+\frac{2}{21}+\frac{2}{91}+\frac{1}{273}+\frac{1}{3003}+0)\\ P(A)=\frac{5}{66}=0.075757576$

Part B:

The conditional probability that the die landed on 3 if all the balls selected are white:

We have to find $P(D_3|A)$

The data required is calculated above:

$P(D_3|A)=\frac{P(A|D_3)P(D_3)}{P(A)}\\ P(D_3|A)=\frac{\frac{2}{91}*\frac{1}{6}}{\frac{5}{66} } \\P(D_3|A)=\frac{22}{455}=0.0483516$

7 0

3 years ago

What is the nth term rule of the quadratic sequence below?<br> -5, -3,3, 13, 27, 45, 67, ...

Svetllana [295]

Answer:

the pattern is +2, +6, +10, +14, +18 etc

so its in increment of 4

the rest is trivial

Step-by-step explanation:

4 0

3 years ago

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