Let the solutions be a and b.
a = -2; b = -10
a + b = -2 + (-10) = -12
ab = (-2)(-10) = 20

(x - a)(x - b) = 0

(x - (-2))(x - (-10)) = 0

(x + 2)(x + 10) = 0

x^2 + 10x + 2x + 20 = 0

x^2 + 12x + 20 = 0

-h = 12

h = -12

4k = 20

k = 5

6 0

3 years ago

Convert 2% to a decimal

Licemer1 [7]

Answer:

0.02

Step-by-step explanation:

is written as an decimal make me brainliest : )

4 0

3 years ago

Resolver la siguiente ecuación por eliminación o sustitución: a-8b= -9 a-2b= -7

Crazy boy [7]

Answer: Solution: $a=\dfrac{-19}{3}$ and $b=\dfrac{1}{3}$ .

Step-by-step explanation:

The given pair of equations:

$a-8b= -9\ ...(i)\\\\ a-2b= -7\ ...(ii)$

Eliminate equation (i) from (ii) , we get

$-2b-(-8b)=-7-(-9)\\\\\Rightarrow\ -2b+8b=-7+9\\\\\Rightarrow\ 6b=2\\\\\Rightarrow\ b=\dfrac{1}{3}$

Put value of b in (ii) , we get

$a-2\times\dfrac{1}{3}=-7\\\\\Rightarrow\ a=-7+\dfrac{2}{3}\\\\\Rightarrow\ a=\dfrac{-21+2}{3}\\\\\Rightarrow\ a=\dfrac{-19}{3}$

Solution: $a=\dfrac{-19}{3}$ and $b=\dfrac{1}{3}$ .

4 0

3 years ago