The first term is a₁ = 2.
Each subsequent term is the reciprocal of the square of the preceding term.
2nd term:
a₂ = 1/2² = 1/4
3rd term:
a₃ = 1/(1/4)² = 1/(1/16) = 16
4th term:
a₄ = 1/16² = 1/256
5th term:
a₅ = 1/(1/256)² = 1/(1/65536) = 65536
The positive square root of the fifth term is
√(65536) = 256
Answer: 256
Answer:
a) Option D) 0.75
b) Option D) 0.3
Step-by-step explanation:
We are given the following in the question:
Percentage of students who choose Western riding = 35%

Percentage of students who choose dressage= 45%

Percentage of students who choose jumping = 50%

Percentage of students who choose both dressage and jumping = 20%

Percentage of students who choose Western and dressage = 10%

Percentage of students who choose Western and jumping = 0%

Thus, we can say

Formula:

a) P(student chooses dressage or jumping)

b) P(student chooses neither dressage nor Western riding)

first invert fraction of the slope from 4/1 to 1/4 and switch sign. then figure out the y-intercept
the algebraic approach would work like this:
-4x + 10 = 1/4x + b
plug in what you got, here: the intersection information
-4*(4) + 10 = 1/4*(4) + b
-16 + 10 = 1 + b
-6 = 1 + b
-7 = b
Answer:
The margin of error for this estimate is of 14.79 yards per game.
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
T interval
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 20 - 1 = 19
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 19 degrees of freedom(y-axis) and a confidence level of
. So we have T = 2.093
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample.
You randomly select 20 games and see that the average yards per game is 273.7 with a standard deviation of 31.64 yards.
This means that 
What is the margin of error for this estimate?



The margin of error for this estimate is of 14.79 yards per game.
It is 6 units because you find the absolute value of the two different coordinates, in this case it is 4 and -2. Since they belong in different quadrants (one x or y value is positive and the other is negative) you add them. If they are both in the same quadrant, you subtract them.