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sergejj [24]
3 years ago
15

Each letter from the word MATHEMATICS is written on a separate slip of paper. The 11th slips of paper are placed in a hat and tw

o slips are drawn at random. If the first letter is not replaced find the probability that the first letter is a vowel (a,e,I,o,u) and the second letter is a vowel
Mathematics
1 answer:
amid [387]3 years ago
6 0
It may be possibly 4 out of 9
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He first term of a sequence is 2, and each subsequent term is the reciprocal of the square of the preceding term. what is the po
polet [3.4K]
The first term is a₁ = 2.
Each subsequent term is the reciprocal of the square of the preceding term.

2nd term:
a₂ = 1/2² = 1/4

3rd term:
a₃ = 1/(1/4)² = 1/(1/16) = 16

4th term:
a₄ = 1/16² = 1/256

5th term:
a₅ = 1/(1/256)² = 1/(1/65536) = 65536
The positive square root of the fifth term is
√(65536) = 256

Answer: 256
4 0
3 years ago
A group of freshmen at a local university consider joining the equestrian team. Thirty‑five percent of students choose Western r
lesantik [10]

Answer:

a) Option D) 0.75

b) Option D) 0.3

Step-by-step explanation:

We are given the following in the question:

Percentage of students who choose Western riding = 35%

P(w) = 0.35

Percentage of students who choose dressage= 45%

P(d) = 0.45

Percentage of students who choose jumping = 50%

P(j) = 0.50

Percentage of students who choose both dressage and jumping = 20%

P(d \cap j) = 0.20

Percentage of students who choose Western and dressage = 10%

P(w \cap d) = 0.10

Percentage of students who choose Western and jumping = 0%

P(w \cap j) = 0

Thus, we can say

P(w \cap j \cap d) = 0

Formula:

P(A \cup B) = P(A) + P(B) - P(A \cap B)

a) P(student chooses dressage or jumping)

P(d \cup j) = P(d) + P(j) -p(d \cap j)\\= 0.45 + 0.50-0.20 = 0.75

b) P(student chooses neither dressage nor Western riding)

= 1 - P(d \cup w)\\= 1 - (P(d) + P(w) - P(d \cap w))\\= 1 - (0.45 + 0.35 - 0.10)= 0.3

5 0
3 years ago
A walking path across a park is represented by the equation y = -4x+10. A
ad-work [718]

first invert fraction of the slope from 4/1 to 1/4 and switch sign. then figure out the y-intercept

the algebraic approach would work like this:

-4x + 10 = 1/4x + b

plug in what you got, here: the intersection information

-4*(4) + 10 = 1/4*(4) + b

-16 + 10 = 1 + b

-6 = 1 + b

-7 = b

3 0
3 years ago
You are curious about the average number of yards Matthew Stafford throws for each game for the Detroit Lions. You randomly sele
Damm [24]

Answer:

The margin of error for this estimate is of 14.79 yards per game.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

T interval

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 20 - 1 = 19

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 19 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.093

The margin of error is:

M = T\frac{s}{\sqrt{n}}

In which s is the standard deviation of the sample and n is the size of the sample.

You randomly select 20 games and see that the average yards per game is 273.7 with a standard deviation of 31.64 yards.

This means that n = 20, s = 31.61

What is the margin of error for this estimate?

M = T\frac{s}{\sqrt{n}}

M = 2.093\frac{31.61}{\sqrt{20}}

M = 14.79

The margin of error for this estimate is of 14.79 yards per game.

3 0
3 years ago
A polygon has the vertices P(-2,6), Q(4,6), R(4,1) and S(-2,1). What is the length of side RS?
inessss [21]
It is 6 units because you find the absolute value of the two different coordinates, in this case it is 4 and -2. Since they belong in different quadrants (one x or y value is positive and the other is negative) you add them. If they are both in the same quadrant, you subtract them. 
8 0
3 years ago
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