Answer:
If the x is multiplication, then the statement is false. If the x is a variable, it is also false.
Step-by-step explanation:
Answer:
Step 1: We make the assumption that 850 is 100% since it is our output value.
Step 2: We next represent the value we seek with $x$x.
Step 3: From step 1, it follows that $100\%=850$100%=850.
Step 4: In the same vein, $x\%=153$x%=153.
Step 5: This gives us a pair of simple equations:
$100\%=850(1)$100%=850(1).
$x\%=153(2)$x%=153(2).
Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS
(left hand side) of both equations have the same unit (%); we have
$\frac{100\%}{x\%}=\frac{850}{153}$
100%
x%=
850
153
Step 7: Taking the inverse (or reciprocal) of both sides yields
$\frac{x\%}{100\%}=\frac{153}{850}$
x%
100%=
153
850
$\Rightarrow x=18\%$⇒x=18%
Therefore, $153$153 is $18\%$18% of $850$850.
Step-by-step explanation:
Got this off of the web ages ago i got a question like this and this is what i wrote
A function could be linear or not. Is the rate of change consistent, increasing, or decreasing? Is does the symbol have one minimum value or maximum value, or several such values?
1a:
580 - (580 × .1) - 20
580 - (58) - 20
522 - 20
502
1b:
990 - (990 × .25) - 20
990 - (247.5) - 20
742.5 - 20
722.5
I'm not sure how to solve #2.