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3 years ago

Esther cut a square paper vertically to make two rectangle pieces. Each rectangle had a perimeter of 63 inches.

Mathematics

2 answers:

chubhunter [2.5K]3 years ago

7 0

Answer:

126 inches

Step-by-step explanation:

I don’t know

mariarad [96]3 years ago

3 0

Answer:

Step-by-step explanation:

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Jessie has a container that contains 18 3/4 cios of ice cream. How many 1/3-cup servings of ice cream are in the container

ladessa [460]

Hi there!

18 × $\frac{3}{4}$ = amount of ice cream in container

13.5 = amount of ice cream in container

Let's replace the number of cups by "C" :

13.5 = C × $\frac{1}{3}$

Isoltate "C" by dividing each side of the equation by $\frac{1}{3}$

40.5 = C

Which means that your answer is : There are 40.5 1/3-cup servings of ice creamin the container!

There you go! I really hope this helped, if there's anything just let me know! :)

7 0

3 years ago

A juice machine is set to dispense 16 ounces of juice. The amount of juice

enyata [817]

Answer:

C. 15.40 ounces to 16.90 ounces

Step-by-step explanation:

7 0

3 years ago

Find the distance between the points.<br> (-3,2) and (0,2)<br> The distance is

irga5000 [103]

Answer:

d=3

Step-by-step explanation:

by using distance formula

d=√(x2-x1)²+(y2-y1)²

let the points be A(-3,2) B(0,2)

d=√(0--3)²+(2-2)²

d=√(+3)²+(0)²

d=√9

d=3

7 0

4 years ago

A person 6ft tall stands 10ft from point P directly beneath a lantern hanging 30 ft above the ground. The lantern start to fall,

xxMikexx [17]

Answer:

$\frac{dL}{dt}=30 \frac{ft}{s}$

Step-by-step explanation:

In order to solve this it is always a good idea to start by drawing a diagram of the situation (See attached picture).

From the diagram we can see that we are dealing with similar triangles. We can use similar triangles to build an equation that relates the length of the shadow with the height of the lamp, so we get:

$\frac{L}{6}=\frac{10+L}{h}$

the height of the lamp can be found by subtracting the $16t^{2}$ distance the lamp falls in a given time t from the original 30ft the lamp was located at.

So the equation will now lok like this:

$\frac{L}{6}=\frac{10+L}{30-16t^{2}}$

So now we can solve the equation for L, we can start by multiplying by the LCD SO WE GET:

$L(30-16t^{2})=6(10+L)$

next, we can distribute the right side of the equation so we get:

$L(30-16t^{2})=60+6L$

and subtract 6L from both sides so we get:

$L(30-16t^{2})-6L=60$

and factor L, so we get:

$L(30-16t^{2}-6)=60$

and solve for L:

$L=\frac{60}{24-16t^{2}}$

now, we can differentiate this equation by using the chain rule, so we get:

$dL=-\frac{60}{(24-16t^{2})^{2}}(-32t)dt$

which can be simplified to:

$\frac{dL}{dt}=\frac{1920t}{(24-16t^{2})^{2}}$

and now we can substitute t for 1s so we get:

$\frac{dL}{dt}=\frac{1920(1)}{(24-16(1)^{2})^{2}}$

$\frac{dL}{dt}=30 \frac{ft}{s}$

7 0

3 years ago

ASK YOUR TEACHER An article reported that for a sample of 42 kitchens with gas cooking appliances monitored during a one-week pe

xxMikexx [17]

Answer:

$654.16-2.02\frac{165.23}{\sqrt{42}}=602.66$

$654.16+2.02\frac{165.23}{\sqrt{42}}=705.66$

So on this case the 95% confidence interval would be given by (602.66;705.66)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=654.16$ represent the sample mean

$\mu$ population mean (variable of interest)

s=165.23 represent the sample standard deviation

n=42 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=42-1=41$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,41)".And we see that $t_{\alpha/2}=2.02$

Now we have everything in order to replace into formula (1):

$654.16-2.02\frac{165.23}{\sqrt{42}}=602.66$

$654.16+2.02\frac{165.23}{\sqrt{42}}=705.66$

So on this case the 95% confidence interval would be given by (602.66;705.66)

7 0

4 years ago