What is the value of x in the equation x-y= 30, when y = 15?

a lemon pie was cut into 6 equal pieces. being on a diet, Matilda ate only half a piece. what fraction of the whole pie did she

WINSTONCH [101]

Matilda only ate 1/12 of the pie as 1/2 of 1/6 = 1/12

5 0

3 years ago

4. A sports car accelerates from rest to a final velocity of 64 m/s at a rate of 12.3

Ivanshal [37]

Answer:

$t = 5.2\ s$

Step-by-step explanation:

Given

$a= 12.3m/s^2$ --- acceleration

$v = 64m/s$ --- final velocity

$u =0m/s$ --- initial velocity (it is 0, because the car starts from rest)

Required

Determine the time taken

This will be solved using Newton's first equation of motion:

$v = u + at$

Substitute values for v, u and a

$64 = 0 + 12.3*t$

$64 = 12.3t$

$12.3t = 64$

Make t the subject

$t = \frac{64}{12.3}$

$t = 5.2\ s$

Hence, the time taken is approximately 5.2 seconds

6 0

3 years ago

4x+3y<12 what’s the answer?

marysya [2.9K]

The answer would be y<-4/3x+4 if it’s 4x+3y<12 if it’s 4x+3y=12 the answer would be y=-4/3x+4. I don’t know what your implying but &12 so if it didn’t help I’m sorry. If this helped please mark me branliest

4 0

3 years ago

70 POINTS! PLEASE HELP! Explain the difference between the following equation formats: Slope-Intercept, Point-Slope and Standard

katrin2010 [14]

Answer and Step-by-step explanation:

1. slope intercept

2. point-slope form

3. standard

Explanation:

1. A slope intercept form equation is when it's set up as y = m x + b

m = slope

b = y-intercept

2. A point-slope form is when a line passes through a point

and the equation is set up as y −b = m ( x−a)

m = slope

(a, b) A point that the line passes through

3. standard lope form is when the equation is set up as

Ax + By = C

7 0

4 years ago

[Calculus] particle at rest question. Show steps, please!

Vinvika [58]

Answer:

E

Step-by-step explanation:

We are given that a particle's position along the x-axis at time t is modeled by:

$x(t)=2t^3-21t^2+72t-53$

And we want to determine at which time(s) t is the particle at rest.

If the particle is at rest, this suggests that its velocity at that time is 0.

Since are we given the position function, we can differentiate it to find the velocity function.

So, by differentiating both sides with respect to t, we acquire:

$\displaystyle x^\prime(t)=v(t)=\frac{d}{dt}\big[2t^3-21t^2+72t-53\big]$

Differentiate. So, our velocity function is:

$v(t)=6t^2-42t+72$

So, we will set the velocity to 0 and solve for t. Hence:

$0=6t^2-42t+72$

We can divide both sides by 6:

$0=t^2-7t+12$

Factoring yields:

$(t-3)(t-4)=0$

By the Zero Product Property:

$t-3\text{ and } t-4=0$

Hence:

$t=3\text{ and } t=4$

Therefore, at the 3rd and 4th seconds, the velocity of the particle is 0, impling that the particle is at rest.

Our answer is E.

6 0

3 years ago