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Rudik [331]
4 years ago
15

If the mean of a positively skewed distribution is 126, which of these values could be the median of the distribution?

Mathematics
2 answers:
Rina8888 [55]4 years ago
8 0

Answer:

It is 122

Step-by-step explanation:

guapka [62]4 years ago
4 0

Answer:

122 is the right answer not 130

Step-by-step explanation:

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$11.25 is what percent of $375?<br> PLS Help Me!!!
Ivahew [28]

11.25/375 = 0.03 which is 3%

4 0
4 years ago
Combine like terms - y + 9z - 16y - 25z + 4
alexandr402 [8]

- 17y - 16z + 4

Step-by-step explanation:

1) Collect like terms.

( - y - 16y) + (9z - 25z) + 4

2) Simplify.

- 17y - 16z + 4

So, therefor, the answer is -17y - 16z + 4.

8 0
3 years ago
a trapezoid has parallel sides of length 26 mm and 44 mm. its other sides measure 10 mm and 17 mm. what is the length of the bim
kirill115 [55]

Answer:

35 mm.

Step-by-step explanation:

That would be (26 + 44)/2

= 70/2

= 35 mm.

5 0
3 years ago
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maria [59]
I think the answer is 9
It's a smaller version of the other figure.
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3 0
3 years ago
A dog is leashed to the corner of a house with a 20 ft long leash. How much running area does the dog have? Round your answer to
11111nata11111 [884]

Answer:

The dog's running area is approximately 942 feet².

Step-by-step explanation:

The dog is leashed to a fixed point, the leash has a length of 20 ft, therefore he can rotate around that point at the maximum distance equal to the length of the leash. This pattern forms a circle, but there is an obstruction, which is the corner of the house. This obstruction takes an arc of the original circle, so the running area of the dog is the area of the whole circle minus the area of the arc formed by the corner of the house.

\text{dog's area} = \text{circle's area} - \text{arc's area}\\\\\text{dog's area} = pi*(20^2) - \frac{90}{360}*pi*(20^2)\\\\\text{dog's area} = \frac{270}{360}*pi*(400)\\\\\text{dog's area} = 942.477\text{ feet}^2

The dog's running area is approximately 942 feet².

3 0
4 years ago
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