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Flura [38]
3 years ago
12

The question is in the photo​

Mathematics
1 answer:
nirvana33 [79]3 years ago
6 0

Answer:

yes

Step-by-step explanation:

half of x which is 4 = y which is 2

you keep doing that with the rest of the xs and ys

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PLEASE HELP!!
I am Lyosha [343]

Answer:

50 stuffed animals and 22 mystery boxes.

Step-by-step explanation:

Firstly, we assign variables.

Let the number of stuffed animals be x and the number of mystery boxes is y

The probability of selecting a stuffed animal is x/72 while the probability is selecting a mystery box is y/72

Now, since the total probability can be 1:

This means that

x/72 + y/72 = 1 •••••••(i)

6 0
2 years ago
Read 2 more answers
Determine the ordered pair that satisfies the equation, 5x + 2y = 7.
AveGali [126]

Answer:

None of the first 4 do. so I guess the answers E.

Step-by-step explanation:

8 0
3 years ago
What is the answer to the question?
Naily [24]
It is 1/3, add up the total number of kids, which is 30, the number of kids 6-8 is 10. 10/30 is equivalent to 1/3
5 0
3 years ago
Read 2 more answers
Given that the expression 2x^3 + mx^2 + nx + c leaves the same remainder when divided by x -2 or by x+1 I prove that m+n =-6
Alla [95]

Given:

The expression is:

2x^3+mx^2+nx+c

It leaves the same remainder when divided by x -2 or by x+1.

To prove:

m+n=-6

Solution:

Remainder theorem: If a polynomial P(x) is divided by (x-c), thent he remainder is P(c).

Let the given polynomial is:

P(x)=2x^3+mx^2+nx+c

It leaves the same remainder when divided by x -2 or by x+1. By using remainder theorem, we can say that

P(2)=P(-1)              ...(i)

Substituting x=-1 in the given polynomial.

P(-1)=2(-1)^3+m(-1)^2+n(-1)+c

P(-1)=-2+m-n+c

Substituting x=2 in the given polynomial.

P(2)=2(2)^3+m(2)^2+n(2)+c

P(2)=2(8)+m(4)+2n+c

P(2)=16+4m+2n+c

Now, substitute the values of P(2) and P(-1) in (i), we get

16+4m+2n+c=-2+m-n+c

16+4m+2n+c+2-m+n-c=0

18+3m+3n=0

3m+3n=-18

Divide both sides by 3.

\dfrac{3m+3n}{3}=\dfrac{-18}{3}

m+n=-6

Hence proved.

7 0
3 years ago
How many ways can three different numbers be selected from 10 numbers to open a keypad lock?
Paraphin [41]

There are 720 ways through which 3 numbers can be selected from 10 numbers to open a keypad lock.

Given that there are 10 numbers are 3 numbers are required to open a keypad lock.

Permutations are the number of ways in which objects can be selected without replacements to form subsets.

It is expressed as nP_{r}=n!/(n-r)!.

Factorial of a number is the product of consecutive numbers less than the number.

Total numbers available=10

Numbers to be selected=3

Number of ways can be found by using permutations.

Number of ways =10P_{3}

=10!/(10-3)!

=10!/7!

=10*9*8*7!/7!

=10*9*8

=720 ways.

Hence there are 720 ways through which 3 numbers can be selected from 10 numbers.

Learn more about permutations at brainly.com/question/1216161

#SPJ1

6 0
2 years ago
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