4 years ago

CAN SOMEBODY PLEASE ANDWER THIS!! Given the function f(x)= 14x^2 + 5x - 1 if you could change the 14 to any other number, but th

e rest has to stay the same, what value would it have to be so that there is only 1 real root for the function? Show or explain.

Mathematics

1 answer:

dybincka [34]4 years ago

4 0

$a {x}^{2} + 5x - 1 = 0 \\ 25 + 4a = 0 \\ a = \frac{ - 25}{4} = - 6.25$

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