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3 years ago

1. Evaluate the expression -6.3a +2(a - b) for a = -2 and b = 1.1.

Mathematics

1 answer:

sasho [114]3 years ago

8 0

Answer:

D or 6.4

Step-by-step explanation:

-6.3*(-2) + 2(-2 - 1.1)

- 6.3 * - 2 = 12.6 Notice that the two minus signs become a +

(-2 - 1.1)= (-3.1) Multiply -3.1 * 2 = - 6.2

12.6 - 6.2 = 6.4

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Select the two values of x that are roots of this equation.

VMariaS [17]

Answer:

x = 2, -3

Step-by-step explanation:

$x^2 + 2x- 6 = 0\\=>x^2 +3x - 2x- 6 = 0\\=>x(x+3) - 2(x +3) = 0\\=> (x-2)(x+3) = 0\\\\$

(x-2) = 0 or (x+3) = 0

x = 2 or x = -3

Thus, two values of x are x = 2, -3

Note: The options given are incorrect.

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3 years ago

Compounds are different than elements because compounds are-

lutik1710 [3]

Step-by-step explanation:

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3 years ago

What is the Answer ????

shusha [124]

Answer: the answer is 8.8

Step-by-step explanation: multiply 2.2 by 4

2.2 X 4

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4 years ago

Read 2 more answers

The mean of a set of numbers is 8, and the mode is 9.

ryzh [129]

You can start by looking at the mode of the set of number automatically b and d are eliminated. We then proceed to calculate the mean so add all the numbers in A so it’ll be, 52 then divide by the amount of numbers in the set so 6. 52/6 =8.6
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3 years ago

Simplify . (1/c + 1/h)/(1/(c ^ 2) - 1/(r ^ 2))

Marrrta [24]

Answer:

$\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}$

Step-by-step explanation:

$\frac{\frac{1}{c}+\frac{1}{h}}{\frac{1}{c^2}-\frac{1}{r^2}}$

Combine $\frac{1}{c} + \frac{1}{h}$

$\frac{\frac{h+c}{ch}}{\frac{1}{c^2}-\frac{1}{r^2}}$

Combine the bottom, too.

$=\frac{\frac{h+c}{ch}}{\frac{r^2-c^2}{c^2r^2}}$

Apply the fraction rule

$=\frac{\left(h+c\right)c^2r^2}{ch\left(r^2-c^2\right)}$

Cancel

$=\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}$

Therefore, $\frac{\left(\frac{1}{c}+\frac{1}{h}\right)}{\left(\frac{1}{\left(c^2\right)}-\frac{1}{\left(r^2\right)}\right)}:\quad \frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}$

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3 years ago