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yan [13]
3 years ago
10

Parallel to Y=3x -18 and goes through (3,2)

Mathematics
1 answer:
wlad13 [49]3 years ago
6 0

Answer:

y = 3x - 7

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 3x - 18 ← is in slope- intercept form

with slope m = 3

Parallel lines have equal slopes, thus

y = 3x + c ← is the partial equation of the parallel line

To find c substitute (3, 2) into the partial equation

2 = 9 + c ⇒ c = 2 - 9 = - 7

y = 3x - 7 ← equation of parallel line

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3 years ago
A computer chess game and a human chess champion are evenly matched. They play ten games. Find probabilities for the following e
AleksAgata [21]

Answer:

(a) The probability that each of them win five games is 0.2461.

(b) The probability that the computer wins seven games is 0.1172.

(c) The probability that the human wins at least 7 games is 0.1711.

Step-by-step explanation:

Let the random variable <em>X</em> = the human wins a chess game.

The probability that the human wins a game is, P (X) = <em>p</em> = 0.50.

The number of games played by the computer and the human is, <em>n </em>= 10.

The random variable X\sim Bin(n = 10,p=0.50)

The probability distribution of the Binomial random variable <em>X</em> is:

P (X=x)={n\choose x}p^{x}(1-p)^{n-x}={10\choose x}(0.50)^{x}(1-0.50)^{10-x}

(a)

If both the computer and the human wins five games each then the probability of the human winning 5 games is:

P (X=5)={10\choose 5}(0.50)^{5}(1-0.50)^{10-5}\\=252\times 0.03125\times0.03125\\=0.246094\\\approx 0.2461

Thus, the probability that each of them win five games is 0.2461.

(b)

If the computer wins 7 games then the number of games won by the human is, 10 - 7 = 3.

P (Computer winning 7 games) = P (Human winning 3 games)

The probability that the human wins 3 games is:

P (X=3)={10\choose 3}(0.50)^{3}(1-0.50)^{10-3}\\=120\times 0.125\times0.0078125\\=0.1171875\\\approx 0.1172

Thus, the probability that the computer wins seven games is 0.1172.

(c)

Compute the probability that the human wins at least 7 games as follows:

P(X\geq 7)=P(X=7)+P(X=8)+P(X=9)+P(X=10)\\={10\choose 7}(0.50)^{7}(1-0.50)^{10-7}+{10\choose 8}(0.50)^{8}(1-0.50)^{10-8}\\+{10\choose 9}(0.50)^{9}(1-0.50)^{10-9}+{10\choose 10}(0.50)^{10}(1-0.50)^{10-10}\\=0.1172+0.044+0.009+0.0009\\=0.1711

Thus, the probability that the human wins at least 7 games is 0.1711.

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3 years ago
What is the sum of the interior angles of a 30-gon??
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180x28 is the sum of the interior angles in a <span>30- gon</span>

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The food bank has 1774.4 oz of chicken.If 12.6 oz is 2 servings,how many servings of chicken does this provide?
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