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Serggg [28]
3 years ago
13

Jordana wrote the equation for a linear relationship as y = -8x-4. For what value of x is y equal to -16

Mathematics
1 answer:
lapo4ka [179]3 years ago
7 0
So our two equations are y=-8x-4 and y=-16, and since in both equations, something equals the same y, those two are the same. So we can combine the two into -16=-8x-4. In the question, they are asking to solve for x. So to do that, you need to isolate your variable. Now for solving algebraic equations, you use reverse PEMDAS (SADMEP), meaning you add 4 to both sides to clear the -4 one the rights side to get -12=-8x. Then you divide both sides by -8 to get 12/8, which simplifies to 3/2. 
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Researchers randomly surveyed people at two amusement parks, Funland and Thrillville, to find out how many times they visit the
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On average, people visit Thrillville 2 more times per year than Funland.

<h3><u>Averages</u></h3>

To determine how many more times per year, on average, do people visit Thrillville than Funland, the following calculation must be performed:

  • Funland: 4,1,2,1,5,6,3,2,4,3,2,6,1,3,2 = 45
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  • Thrillville: 8,6,5,7,2,5,4,2,1,9,3,8,3,7,5,2,9,4,2,8 = 100
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  • 5 - 3 = 2

Therefore, on average, people visit Thrillville 2 more times per year than Funland.

Learn more about averages in brainly.com/question/2426692

4 0
2 years ago
 The area of a circle is less than 1 dm². Find the radius of the circle. The area of a circle is less than 1 dm². Find the rad
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3 years ago
What fraction of a day is 14 hours
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7 0
3 years ago
Read 2 more answers
Consider triangle ABC. The legs have a length of 5 units each. What is the length of the hypotenuse of the triangle?
Korvikt [17]

Answer:

5\sqrt{2} units.

Step-by-step explanation:

We have been given that two legs of triangle ABC measures 5 units each. We are asked to find the length of the hypotenuse.

We will use Pythagoras theorem to solve for the hypotenuse of triangle ABC.

\text{Hypotenuse}^2=\text{Leg}^2+\text{Leg}^2

Substituting our given values in above equation we will get,

\text{Hypotenuse}^2=5^2+5^2

\text{Hypotenuse}^2=25+25

\text{Hypotenuse}^2=50

Upon taking square root of both sides of our equation we will get,

\text{Hypotenuse}=\sqrt{50}

\text{Hypotenuse}=\sqrt{25*2}

\text{Hypotenuse}=5\sqrt{2}

Therefore, the length of hypotenuse of triangle ABC is 5\sqrt{2} units.

6 0
3 years ago
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