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Serggg [28]
2 years ago
13

Jordana wrote the equation for a linear relationship as y = -8x-4. For what value of x is y equal to -16

Mathematics
1 answer:
lapo4ka [179]2 years ago
7 0
So our two equations are y=-8x-4 and y=-16, and since in both equations, something equals the same y, those two are the same. So we can combine the two into -16=-8x-4. In the question, they are asking to solve for x. So to do that, you need to isolate your variable. Now for solving algebraic equations, you use reverse PEMDAS (SADMEP), meaning you add 4 to both sides to clear the -4 one the rights side to get -12=-8x. Then you divide both sides by -8 to get 12/8, which simplifies to 3/2. 
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what is the circumference of a circle with a radius of 6.1 centimeters? enter your answer as a decimal in the box. use 3.14 for
Savatey [412]
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So 2*3.14*6.1 = 38.308

To the nearest tenth, the answer is 38.3 cm
8 0
3 years ago
Write an equation in slope-intercept form for the line that satisfies each set of conditions.
finlep [7]

Answer: Y= 2/3x + 9

Explanation: The equation is in slope-intercept form, y=mx+b. Since it is parallel to the equation, it has the same slope (2/3x) and since b is the x intercept, b is 9.

7 0
3 years ago
Determine the sample size needed to construct a 90% confidence interval to estimate the population proportion when p = 0.65 and
WINSTONCH [101]

Answer:

n=170

Step-by-step explanation:

1) Notation and definitions

n random sample taken (variable of interest)

\hat p=0.65 estimated proportion.

p true population

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by \alpha=1-0.90=0.1 and \alpha/2 =0.05. And the critical value would be given by:

z_{\alpha/2}=\pm 1.64

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.06 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.65(1-0.65)}{(\frac{0.06}{1.64})^2}=169.968  

And rounded up we have that n=170

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Step-by-step explanation:

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