(33)(1/9•2-6+2)
18-6+2=14
33•1/14 = 33/14
The answer is 33/14 or 2.35714
Answer:
The total number of unbroken / working slots
Step-by-step explanation:
Given that Devin's DVD case has 3 rows of slots, but 5 slots are broken
Also given that the number of slots in a row is x
1 row has x slots
3 rows has y slots
on cross multiplication we get y = 3x
ie there are a total of 3x slots in the 3 rows
Given that out of these 3x slots 5 . of the slots are broken
Therefore the total number of working slots = total number of slots - number of slots which are broken
total number of working slots are = 3x - 5
Therefore the given expression is the number of working / good slots
Answer:
37 lbs.
Step-by-step explanation:
There is a multiple zero at 0 (which means that it touches there), and there are single zeros at -2 and 2 (which means that they cross). There is also 2 imaginary zeros at i and -i.
You can find this by factoring. Start by pulling out the greatest common factor, which in this case is -x^2.
-x^6 + 3x^4 + 4x^2
-x^2(x^4 - 3x^2 - 4)
Now we can factor the inside of the parenthesis. You do this by finding factors of the last number that add up to the middle number.
-x^2(x^4 - 3x^2 - 4)
-x^2(x^2 - 4)(x^2 + 1)
Now we can use the factors of two perfect squares rule to factor the middle parenthesis.
-x^2(x^2 - 4)(x^2 + 1)
-x^2(x - 2)(x + 2)(x^2 + 1)
We would also want to split the term in the front.
-x^2(x - 2)(x + 2)(x^2 + 1)
(x)(-x)(x - 2)(x + 2)(x^2 + 1)
Now we would set each portion equal to 0 and solve.
First root
x = 0 ---> no work needed
Second root
-x = 0 ---> divide by -1
x = 0
Third root
x - 2 = 0
x = 2
Forth root
x + 2 = 0
x = -2
Fifth and Sixth roots
x^2 + 1 = 0
x^2 = -1
x = +/-
x = +/- i
b= 2 and 5
is your answer to the above question.