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3 years ago

Solve the following equation, answer as a reduced, mixed number. Then place the correct number in the box provided.

2 answers:

4 0

7(x-2) + 3(x + 2) = 5(x-6)...distribute thru the parenthesis
7x - 14 + 3x + 6 = 5x - 30...combine like terms
10x - 8 = 5x - 30...subtract 5x from both sides
10x - 5x - 8 = -30....add 8 to both sides
10x - 5x = -30 + 8...combine like terms
5x = - 22
x = -22/5 = - 4 2/5 <==

liq [111]3 years ago

4 0

the correct answer is x = - 4 2/5

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A bus covers a distance of 2.45 km in 2 min. What is the speed of bus?

Vladimir [108]

Answer:

The speed of the bus is 74.242 kilometers per hour.

Step-by-step explanation:

Let suppose that bus runs at constant speed and that speed is measured in kilometers per hour. Then, the speed of the bus ( $v$ ), in kiometers per hour, is determined by following kinematic expression:

$v = \frac{s}{t}$ (1)

Where:

$s$ - Travelled distance, in kilometers.

$t$ - Time, in hours.

If we know that $s = 2.45\,km$ and $t = 0.033\,h$ , then the speed of the bus is:

$v = \frac{s}{t}$

$v = 74.242\,\frac{km}{h}$

The speed of the bus is 74.242 kilometers per hour.

7 0

3 years ago

12 whites 4 blacks 3 blue 1 red. Find each experimental probability as a fraction? 1.)p(white)

Dafna1 [17]

Experimental probability is if an experiment was actually run. If those values are the result of an experiment, then the probability is desired value (white) over total possibilities.

$\frac{12}{20} = \frac{3}{5}$ or 0.6

5 0

3 years ago

Taylor is comparing the prices of two mattress cleaning companies. Company A charges $30 per mattress and an additional $15 as s

Oduvanchick [21]

part A:

company a

30m+15

m= matress

company b

28m+21

m=matresses sold

part B:

company a

30(6)+15

195$

company b

28(6)+21

189$

company B charges less

part C:

company a

30(3)+15

105$

company b

28(3)+21

105$

there is no change at all so you do not save anything.

3 0

3 years ago

How would I turn 0.46 into a fraction

Pepsi [2]

Step 1: 0.46 = 46⁄100
Step 2: Simplify 46⁄100 = 23⁄50 hope this helped u

6 0

3 years ago

Read 2 more answers

Arm Span(x) Height(y)

natita [175]

Answer:

Here's what I get.

Step-by-step explanation:

1. Representation of data

I used Excel to create a scatterplot of the data, draw the line of best fit, and print the regression equation.

2. Line of best fit

(a) Variables

I chose arm span as the dependent variable (y-axis) and height as the independent variable (x-axis).

It seems to me that arm span depends on your height rather than the other way around.

(b) Regression equation

The calculation is easy but tedious, so I asked Excel to do it.

For the equation y = ax + b, the formulas are

$a = \dfrac{\sum y \sum x^{2} - \sum x \sumxy}{n\sum x^{2}- \left (\sum x\right )^{2}}\\\\b = \dfrac{n\sumx y - \sum x \sumxy}{n\sum x^{2}- \left (\sum x\right )^{2}}$

This gave the regression equation:

y = 1.0595x - 4.1524

(c) Interpretation

The line shows how arm span depends on height.

The slope of the line says that arm span increases about 6 % faster than height.

The y-intercept is -4. If your height is zero, your arm length is -4 in (both are impossible).

(d) Residuals

$\begin{array}{cccr}&\textbf{Arm Span} & \textbf{Arm Span}&\\\textbf{Height/in} &\textbf{Actual} & \textbf{Predicted}&\textbf{Residual}\\25 & 19 & 22.3 & -3.3\\40 & 41 & 38.2 & 2.8\\55 & 51 & 54.1 & -3.1\\65 & 67 & 62.6 & 4.4\\ \end{array}$

The residuals appear to be evenly distributed above and below the predicted values.

A graph of all the residuals confirms this observation.

The equation usually predicts arm span to within 4 in.

(e) Predictions

(i) Height of person with 66 in arm span

$\begin{array}{rcl}y& = & 1.0595x - 4.1524\\66 & = & 1.0595x - 4.1524\\70.1524 & = & 1.0595x\\x & = & \dfrac{70.1524}{1.0595}\\\\& = & \textbf{66 in}\\\end{array}\\\text{A person with an arm span of 66 in should have a height of about $\large \boxed{\textbf{66 in}}$}$

(ii) Arm span of 74 in tall person

$\begin{array}{rcl}y& = & 1.0595x - 4.1524\\& = & 1.0595\times74 - 4.1524\\& = & 78.4030 - 4.1524\\& = & \textbf{74 in}\\\end{array}\\\text{ A person who is 74 in tall should have an arm span of $\large \boxed{\textbf{74 in}}$}$

6 0

3 years ago