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inn [45]
3 years ago
9

line m passes through the points (6,1)and(2,-3).line n passes through the points (2,3)and(5,-6).find the point of intersection o

f these lines
Mathematics
1 answer:
scoundrel [369]3 years ago
6 0
So, first you need to put both of them in Point slope. They are, y - 1= 1(x-6) and y - 3 = -3 (x-2). Make them both slope intercept. Which is, y=x-7 and y=-3x-3. Then, g=find the point of interception. Which is, (1,-6)
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Solve with explanation (3)
grin007 [14]

Answer:

a = 66⁰

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Step-by-step explanation:

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a = 180 - 114

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To calculate b⁰;

Line AB = Line BC, thus, ∠BAC = ∠BCA

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4 0
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Sin(x2 y2 da r , where r is the region in the first quadrant between the circles with center the origin and radii 1 and 5
Rudik [331]
I assume there's a plus sign missing above...

Convert to polar coordinates, using

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Then the Jacobian is

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Then

\mathrm dA=\mathrm dx\,\mathrm dy=|-r|\,\mathrm dr\,\mathrm d\theta=r\,\mathrm dr\,\mathrm d\theta

so the integral can be written as

\displaystyle\iint_R\sin(x^2+y^2)\,\mathrm dA=\int_0^{\pi/2}\int_1^5r\sin(r^2)\,\mathrm dr\,\mathrm d\theta

Let s=r^2, so that \dfrac{\mathrm ds}2=r\,\mathrm dr.

\displaystyle\frac12\int_0^{\pi/2}\int_1^{25}\sin s\,\mathrm ds\,\mathrm d\theta=-\frac12(\cos25-\cos1)\int_0^{\pi/2}\mathrm d\theta=\frac\pi4(\cos1-\cos25)
3 0
3 years ago
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