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2 years ago

Translate “the sum of 6 and the product of 8 and x” into a mathematical expression

Mathematics

2 answers:

My name is Ann [436]2 years ago

7 0

For this case we must rewrite the given expression mathematically.

The sum of 6 and something else is written as:

$6+$

The product of 8 and x is written as:

$8x$

Finally, the expression is given by:

$6 + 8x$

Answer:

The expression is given by:

$6 + 8x$

nexus9112 [7]2 years ago

3 0

Answer:

8x+ 6 is the translated mathematical expression.

Step-by-step explanation:

We are given the following English expression which are to translate into a mathematical expression:

'The sum of 6 and the product of 8 and x” into a mathematical expression'

Translating it in small chunks:

1. the sum of 6 ---> +6

2. product of 8 and x ---> 8x

Therefore, combining these we get the mathematical expression 8x + 6

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Answer:

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Where $\mu=17$ and $\sigma=5.6$

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

Part a

The mean is $\mu_{\bar x }= 17$

Part b

And the deviation:

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Step-by-step explanation:

Assuming this complete info: Suppose a random variable xx is normally distributed with μ=17 and σ=5.6. According to the Central Limit Theorem, for samples of size 13:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(17,5.6)$

Where $\mu=17$ and $\sigma=5.6$

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

Part a

The mean is $\mu_{\bar x }= 17$

Part b

And the deviation:

$\sigma_{\bar X}= \frac{5.6}{\sqrt{13}}= 1.553$

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Step-by-step explanation:

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Answer:

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