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3 years ago

Translate “the sum of 6 and the product of 8 and x” into a mathematical expression

Mathematics

2 answers:

My name is Ann [436]3 years ago

7 0

For this case we must rewrite the given expression mathematically.

The sum of 6 and something else is written as:

$6+$

The product of 8 and x is written as:

$8x$

Finally, the expression is given by:

$6 + 8x$

Answer:

The expression is given by:

$6 + 8x$

nexus9112 [7]3 years ago

3 0

Answer:

8x+ 6 is the translated mathematical expression.

Step-by-step explanation:

We are given the following English expression which are to translate into a mathematical expression:

'The sum of 6 and the product of 8 and x” into a mathematical expression'

Translating it in small chunks:

1. the sum of 6 ---> +6

2. product of 8 and x ---> 8x

Therefore, combining these we get the mathematical expression 8x + 6

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Answer:

0.87 which is 13/15

Step-by-step explanation:

6/5 becomes 18/15

3/3 becomes 15/15

18/15-15/15 is 13/15

13 divided by 15 is about 0.87

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3 years ago

An oil refinery is located on the north bank of a straight river that is 2 km wide. A pipeline is to be constructed from the ref

hichkok12 [17]

Answer:

P is exactly 3km east from the oil refinery.

Step-by-step explanation:

Let's d be the distance in km from the oil refinery to point P. So the horizontal distance from P to the storage is 3 - d and the vertical distance is 2. Hence the diagonal distance is:

$\sqrt{(3 - d)^2 + 2^2} = \sqrt{(3 - d)^2 + 4}$

So the cost of laying pipe under water with this distance is

$800000\sqrt{(3 - d)^2 + 4}$

And the cost of laying pipe over land from the refinery to point P is 400000d. Hence the total cost:

$800000\sqrt{(3 - d)^2 + 4} + 400000d$

We can find the minimum value of this by taking the 1st derivative and set it to 0

$800000\frac{2*0.5*(3-d)(-1)}{\sqrt{(3 - d)^2 + 4}} + 400000 = 0$

We can move the first term over to the right hand side and divide both sides by 400000

$1 = 2\frac{3 - d}{\sqrt{(3 - d)^2 + 4}}$

$\sqrt{(3 - d)^2 + 4} = 6 - 2d$

From here we can square up both sides

$(3 - d)^2 + 4 = (6 - 2d)^2$

$9 - 6d + d^2 + 4 = 36 - 24d + 4d^2$

$3d^2-18d+27 = 0$

$d^2 - 6d + 9 = 0$

$(d - 3)^2 = 0$

$d -3 = 0$

d = 3

So the cost of pipeline is minimum when P is exactly 3km east from the oil refinery.

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