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valina [46]
3 years ago
7

Jeremiah always rides his bike to and from work the total length of the trip to and from work is 14.6 kilometers last month Jere

miah worked 18 days how many kilometers did he ride his bike to and from work last month
Mathematics
1 answer:
dezoksy [38]3 years ago
8 0

Answer:

As per the given statement: Jeremiah always rides his bike to and from work the total length of the trip to and from work is 14.6 kilometers last month.

⇒\text{Total length of the trip to and fro from work last month} = 14.6 km

Also, it is given that Jeremiah worked 18 days.

then;

\text{Total distance he ride his bike} = 14.6 \times 18 = \frac{146}{10} \times 18 = \frac{146 \times 18}{10} = \frac{2628}{10}

Simplify:

\text{Total distance he ride his bike} = 262.8 km

Therefore, 262.8 km did he rode his bike to and from work last month

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Answer:

6x+2

Step-by-step explanation:

your combine like terms...

so 13x is teh same as -7x

13x-7x= 6x

3 and -1 are the same as well

3-1=2

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6x+2

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Please help with any of this Im stuck and having trouble with pre calc is it basic triogmetric identities using quotient and rec
german

How I was taught all of these problems is in terms of r, x, and y. Where sin = y/r, cos = x/r, tan = y/x, csc = r/y, sec = r/x, cot = x/y. That is how I will designate all of the specific pieces in each problem.

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Let's start with sin here. \frac{2\sqrt{5}}{5} = \frac{2}{\sqrt{5}} Therefore, because sin is y/r, r = \sqrt{5} and y = +2. Moving over to cot, which is x/y, x = -1, and y = 2. We know y has to be positive because it is positive in our given value of sin. Now, to find cos, we have to do x/r.

cos = \frac{-1}{\sqrt{5}} = \frac{-\sqrt{5}}{5}

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Let's start with secant here. Secant is r/x, where r (the length value/hypotenuse) cannot be negative. So, r = 9 and x = -7. Moving over to tan, x must still equal -7, and y = 4\sqrt{2}. Now, to find csc, we have to do r/y.

csc = \frac{9}{4\sqrt{2}} = \frac{9\sqrt{2}}{8}

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sin^2 + cos^2 = 1,

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tan^2 + 1 = sec^2.

#5

Let's take a look at the information given here. We know that cos = -3/4, and sin (the y value), must be greater than 0. To find sin, we can use the first pythagorean identity.

sin^2 + (-3/4)^2 = 1

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#6

Let's take a look at the information given here. If we know that csc is negative, then our y value must also be negative (r will never be negative). So, if cot must be positive, then our x value must also be negative (a negative divided by a negative makes a positive). Let's use the second pythagorean identity to solve for cot.

1 + cot^2 = (\frac{-\sqrt{6}}{2})^{2}

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