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valina [46]
3 years ago
7

Jeremiah always rides his bike to and from work the total length of the trip to and from work is 14.6 kilometers last month Jere

miah worked 18 days how many kilometers did he ride his bike to and from work last month
Mathematics
1 answer:
dezoksy [38]3 years ago
8 0

Answer:

As per the given statement: Jeremiah always rides his bike to and from work the total length of the trip to and from work is 14.6 kilometers last month.

⇒\text{Total length of the trip to and fro from work last month} = 14.6 km

Also, it is given that Jeremiah worked 18 days.

then;

\text{Total distance he ride his bike} = 14.6 \times 18 = \frac{146}{10} \times 18 = \frac{146 \times 18}{10} = \frac{2628}{10}

Simplify:

\text{Total distance he ride his bike} = 262.8 km

Therefore, 262.8 km did he rode his bike to and from work last month

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Mahnoor randomly selects times to walk into a local restaurant and observe the type of music being played She found that the res
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Answer:

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Observed number   11            17                 8      

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Step-by-step explanation:

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Observed number 11            17                 8         36

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Question 3 A study was performed to determine whether men and women differ in their repeatability in assembling components on pr
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Answer:

There is no sufficient evidence to support the claim that men and women differ in repeatability for this assembly task

Step-by-step explanation:

Given

Let subscript 1 represent men and 2 represent women, respectively.

n_1 = 25

n_2 = 21

s_1 = 0.98

s_2 = 1.02

\alpha = 0.02

Required

Determine if here is enough evidence

First, we need to state the hypotheses

H_o: \sigma_1^2 = \sigma_2^2

H_1: \sigma_1^2 \ne \sigma_2^2

Next, calculate the test statistic using:

F = \frac{s_1^2}{s_2^2}

F = \frac{0.98^2}{1.02^2}

F = 0.923

Calculate the rejection region;

But first, calculate the degrees of freedom

df_1 =n_1 - 1

df_1 =25 - 1

df_1 =24

df_2 = n_2 -1

df_2 = 21 - 1

df_2 = 20

Using the F Distribution:  table

c = \frac{\alpha}{2}

c = \frac{0.02}{2}

c = 0.01

At 0.01 level (check row 20 and column 24), the critical value is:

<em></em>f_{0.01,24,20} = 2.86<em> --- the upper bound</em>

At 0.01 level (check row 24 and column 20), the critical value is:

f_{0.01,20,24} = 2.74

Calculate the inverse F distribution.

f_{0.99,20,24} = \frac{1}{f_{0.01,20,24}} = \frac{1}{2.74} =0.365 ---- the lower bound

The rejection region is then represented as:

0.365 < Test\ Statistic < 2.86

If the test statistic falls within this region, then the null hypothesis is rejected

F = 0.923 --- Test Statistic

0.365 < 0.923 < 2.86

<em>The above inequality is true; so, the null hypothesis is rejected.</em>

<em>This implies that, there is no sufficient evidence.</em>

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Answer:

Option 1

Step-by-step explanation:

Arc MK is equal to the sum of arcs ML and LK.

6 0
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