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3 years ago

What is between 280 and 560?

Mathematics

1 answer:

nikitadnepr [17]3 years ago

3 0

420 would be the middle number.

Hoped I Could Help:)

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Which are the solutions of the quadratic equation? x2 = 9x + 6

Lelechka [254]

X^2 = 9x + 6
x^2 - 9x - 6 = 0
use quadratic formula : (-b (+-) sqrt b^2 - 4ac) / (2a)
a = 1, b = -9, c = -6
now we sub

x = (-(-9) (+-) sqrt -9^2 - 4(1)(-6)) / 2(1)
x = 9 (+-) sqrt 81 + 24)/2
x = 9 (+-) sqrt 105) / 2
x = 9/2 + 1/2 sqrt 105 or x = 9/2 - 1/2 sqrt 105

8 0

3 years ago

Read 2 more answers

Solve for a side in right triangles

natita [175]

Answer:

2.30

Step-by-step explanation:

The side of interest is opposite the given angle, and the hypotenuse is given. The sine relation tells you ...

sin(A) = a/c

a = c·sin(A) = 3·sin(50°)

a = BC ≈ 2.2981 ≈ 2.30

5 0

3 years ago

PLEASE HELP I WILL MARK BRAINLIEST

krok68 [10]

Answer:

Option 2

Step-by-step explanation:

Because it shows that it is going up in a half not a whole.

3 0

3 years ago

A rectangular tank is 24 cm wide, and 30 cm long. It contains a stone and is filled with water to a height of 8 cm. When Amy pul

maw [93]

Answer:

Formula for volume = length (L) × width (W) × height (H)

Volume of the stone = 1,440 cm³

Step-by-step explanation:

✔️Formula for the rectangular tank = L*W*H

✔️Volume of the stone = volume of the tank with the stone - volume of the tank without the stone

✔️Volume of the tank with the stone:

L = 30 cm, W = 24 cm, H = 8 cm (height of water when the stone was in the tank)

Volume of the tank with the stone = 30*24*8 = 5,760 cm³

✔️Volume of the tank without the stone:

L = 30 cm, W = 24 cm, H = 6 cm (height of water when the stone was pulled out)

Volume of the tank with the stone = 30*24*6 = 4,320 cm³

✅Volume of the stone = 5,760 - 4,320 = 1,440 cm³

3 0

3 years ago

Researchers interviewed street prostitutes in Canada and the United States. The mean age of the 100 Canadian prostitutes upon en

levacccp [35]

Answer:

Step-by-step explanation:

The null and the alternative hypothesis is:

$H_o: \mu_c \ge \mu_{us}$

$H_a : \mu_c < \mu_{us}$

The t- student test statistics can be computed as:

$t = \dfrac{x_c- x_{us}}{\sqrt{\dfrac{\sigma_c^2}{n_c} + \dfrac{\sigma_{us}^2}{n_{us}} }}$

$t = \dfrac{19- 21}{\sqrt{\dfrac{7^2}{100} + \dfrac{8^2}{130} }}$

t = -2.017

degree of freedom = (n₁ - 1) + (n₂ - 1)

= (100 - 1) + (130 - 1)

= 228

Using the data of t-value and degree of freedom;

The P-value = -0.224

Decision rule: Do not reject the null hypothesis if the p-value is greater than ∝(0.01)

Conclusion: We reject the null hypothesis since the p-value is less than ∝.

Therefore, there is enough evidence to conclude that the mean age of entering prostitution in Canada is lower than that of the United States.

5 0

3 years ago