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3 years ago

What is the length of a hypotenuse when the legs are 5 and 12

1 answer:

8 0

By using pythagoras theorem where
(Base)^2 +(perpedicular)^2 = (hypotenuse)^2
So,
(5)^2 +(12)^2 = (hypotenuse)^2
25 + 144 = (hypotenuse)^2
169 = (hypotenuse)^2
13 = hypotenuse

So, hypotenuse = 13

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Which of the following accurately depicts the transformation of y= x^2 to the function shown below? y=2(x-3)^2+5

sweet [91]

Answer:

Which of the following accurately depicts the transformation of y= x^2 to the function shown below? y=2(x-3)^2+5

A. Shift left 3 units, shrink vertically to 1/2 of the original height, then shift up 5 units.

B. Shift right 3 units, stretch vertically by a factor of 2, then shift up 5 units.

C. Shift up 3 units, stretch horizontally by a factor of 2, then shift left 5 units.

D. Shift 5 units right, stretch vertically by a factor of 3, then shift up 2 units.

Step-by-step explanation:

For f(x) = 4x+1 and g(x)= x^2-5, find (f/g) (x).

6 0

3 years ago

Plsssssss answer fast

stellarik [79]

B, x=12 because 140-80=60, 60/5=12

8 0

2 years ago

Determine the volume of the parallelepiped with one vertex at the origin and the three vertices adjacent to it at (2, â1, â1), (

valentinak56 [21]

Answer:

Step-by-step explanation:

Here is the complete question

Find the volume of the parallelepiped with one vertex at the origin and adjacent vertices at (1, 0, -3), (1, 2, 4), and (5, 1, 0).

Solution

We find the volume of the parallelepiped by making a 3 × 3 column matrix whose columns are the corresponding coordinates of the vertices of the parallelepiped.

So, (1, 0, -3), (1, 2, 4) and (5, 1, 0)

$A = \left[\begin{array}{ccc}1&1&5\\0&2&1\\-3&4&0\end{array}\right]$

The determinant of A is the volume of the parallelepiped. So,

detA = 1(2 × 0 - 4 × 1) - 1(0 × 0 - (-3) × 1) + 5(0 × 4 - (-3) × 2)

= 1(0 - 4) - 1(0 + 3) + 5(0 + 6)

= 1(-4) - 1(3) + 5(6)

= -4 - 3 + 30

= 23

So the volume of the parallelepiped is 23

4 0

2 years ago

Find the difference. 5wx2 - 2wx2 A. 3 B. 2wx2 C. 3wx2 D. 4wx2

scoray [572]

$5wx2-2wx2 :$

$5-2 wx2$

$= 3 wx2$

Answer C

hope this helps!

7 0

4 years ago

Use cavalieri's Principle to calculate the exact of an oblique cylinder with a radius of 10 meters and a height of 11 meters.

Readme [11.4K]

Am I to assume this is for volume? The volume formula for a cylinder...oblique or not...is V = 1/3pi r^2 h. Cavalieri's principle tells us that the formulas for both are the same. So V = 1/3*pi*100*11 and V = 366.67 pi

8 0

3 years ago

Read 2 more answers