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Kipish [7]
4 years ago
10

How do you solve for m using the equation 5.01cm^3=m/1.2cm^3

Mathematics
1 answer:
4vir4ik [10]4 years ago
5 0
5.01/1.2=m
M=4.175
So your answer for M is 4.175
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Use implicit differentiation to find y^1 for the equation y^2-y-4x=0
Rudik [331]

Answer:

Step-by-step explanation:

y²-y-4x=0

differentiate w.r.t. x

2y*y^1-y^1-4=0

(2y-1)y^1=4

y^1=4/(2y-1)

3 0
3 years ago
Help me somebody if you want to help me
elena55 [62]

Answer:

A=πr²=π·3²≈28.27433

To find the area of a circle, use the equation πr²

The image is a bit blurry so from what I saw r (radius) is 3 otherwise you can use this equation if r is not 3.

If π was replaced with 3.14 the answer is 28.26 ft².

8 0
3 years ago
In a class of students, the following data table summarizes how many students have a brother or a sister. What is the probabilit
kondor19780726 [428]

Answer:

22/29

Step-by-step explanation:

Idk

6 0
3 years ago
The area of a square shaped yard is 201.5 ft2. Which measurement is closest to the side length of this yard in feet?
Aleonysh [2.5K]

Answer:

a = 14.19 feet

Step-by-step explanation:

Given that,

The area of a square shaped yard is 201.5 ft²

We need to find the side length of this yard in feet.

The area of a square shaped object is given by :

A = a², a is the side length of the object

Put A = 201.5 ft² in above formula,

201.5=a^2\\\\a=\sqrt{201.5 } \\\\a=14.19\ \text{feet}

So, the side of the square yard is 14.19 feet.

8 0
3 years ago
A poll was taken this year asking college students if they considered themselves overweight. A similar poll was taken 5 years ag
Katyanochek1 [597]

Answer:

At 5% significance level, it is statistically evident that    there is nodifference in the proportion of college students who consider themselves overweight between the two poll                                  

Step-by-step explanation:

Given that a poll was taken this year asking college students if they considered themselves overweight. A similar poll was taken 5 years ago.

Let five years ago be group I X and as of now be group II Y

H_0: p_x =p_y\\H_a: p_x \neq p_y

(Two tailed test at 5% level of significance)

                Group I            Group II              combined p

n                  270                 300                         570

favor            120                  140                          260

p                   0.4444            0.4667                   0.4561

Std error   for differene = \sqrt{\frac{0.4561(1-0.4561)}{570} } \\=0.0209

p difference = -0.0223    

Z statistic = p diff/std error =       -1.066

p value =0.2864

Since p value >0.05, we accept null hypothesis.

        At 5% significance level, it is statistically evident that    there is nodifference in the proportion of college students who consider themselves overweight between the two poll                                  

7 0
3 years ago
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