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3 years ago

A car servicing station is running a special offer. The breakdown of the cost for different services is given below.

Mathematics

1 answer:

mrs_skeptik [129]3 years ago

4 0

Answer:

Option C

Step-by-step explanation:

There are several types of costs in this problem:

* Unique costs

* Costs that depend on the number of cars

* Costs that depend on the number of months

* Costs that depend on the number of months and the number of cars.

The costs that depend on the number of cars represent the coefficient of the variable n.

The costs that do not depend on the number of cars represent the constant value of the equation.

Then, to solve this problem you must identify the costs that do not depend on the number of cars.

These costs are:

* Membership Fee: $ 50 (one-time cost)

* Pull Pressure Check Cost: $ 15 per month

$\$50 + \$15(12\ month) = \$230$

Then the answer is option C

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zubka84 [21]

Answer:

$3\,log (x-2)+2\,log(x+2)$ can be written as the single logarithm:

$log((x-2)^3\,(x+2)^2)$

Step-by-step explanation:

Start by using in both terms of the expression the property of logarithm of a power that states:

$log(a^b)=b\,*\,log(a)$

so we recognize that the factor that multiplies each logarithmic expression, can be understood as the power of the argument of the function logarithm:

$3\,log(x-2)=log((x-2)^3)\\and\\2\,log(x+2)=log((x+2)^2)$

Then we use the property of logarithm of a product which states that:

$log(a*b)=log(a)+log(b)$

So now we recognize the expression:

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as the logarithm of the product:

$log((x-2)^3\,(x+2)^2)$

which is finally a single logarithm as requested.

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3 years ago

An experiment consists of spining the spinner once.What is the probability of landing on a 2 ?

asambeis [7]

The probability of the spinner landing on 2 is

<em>1 / (the total number of different places it COULD land on) .</em>

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3 years ago

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mezya [45]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

PLEASE HELP...

joja [24]

Answer:

$10,240

Step-by-step explanation:

y = 20,000 (.80)^t

y = 20,000 (0.80)^3

0.8^3 = 0.512

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3 years ago

1) A light bulb producing company states that its lights will last an average of 1200 hours with a standard deviation of 200 hou

Ronch [10]

The mean ( average ) is given as 1200 hours.

The standard deviation is 200, sample size is 100.

Find the standard error:

√(200^2 / 100) = 20

Now calculate the confidence interval. For 95% the Z number is 1.96

Multiply Z by the standard error:

1.96 x 20 =39.2

Now find the range that the mean should be within:

1200 - 39.2 = 1160.8

1200 + 39.2 = 1239.2

The samples should be between 1160.8 and 1239.2 for a 95% confidence interval.

Since the average was 1050, which is below 1160.8 the bulbs are not in compliance.

4 0

4 years ago