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madreJ [45]
3 years ago
11

A high school teacher gives three regular exams during a semester and one final exam at the end of the semester. A student’s fin

al grade is found by taking of the student’s three regular exam scores and then adding 40% of the student’s final exam score. Sophia earned scores of 78, 92, and 80 on the three regular exams and a score of 90 on the final exam. What is Sophia’s final grade?
Mathematics
1 answer:
statuscvo [17]3 years ago
5 0
To get an average score of 80% (out of four exams), a total of 4*80%=320% is needed, so the minimum required for the 4th test is 320-(75+97+60)=88.
To get an average score of 89% (out of four exams), a total of 4*89%=356% is needed, so the maximum required for the 4th test is 356-(75+97+60)=124, which is impossible.
So the next exam grade must range between 88 and 100 to get a grade b in the class.

Hoped I help! Mark brainly it would help<3
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Show with work please.
kolbaska11 [484]

Answer:

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

Step-by-step explanation:

The identity you will use is:

$\csc \left(x\right)=\frac{1}{\sin \left(x\right)}$

So,

$\csc \left(\theta-\frac{\pi }{2}\right)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{\sin \left(-\frac{\pi }{2}+\theta\right)}$

Now, using the difference of sin

Note: state that \text{sin}(\alpha\pm \beta)=\text{sin}(\alpha) \text{cos}(\beta) \pm \text{cos}(\alpha) \text{sin}(\beta)

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)}$

Solving the difference of sin:

$-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)$

-\cos \left(\theta\right) \cdot 1+0\cdot \sin \left(\theta\right)

-\text{cos} \left(\theta\right)

Then,

$\csc \left(\theta-\frac{\pi }{2}\right)=-\frac{1}{\cos \left(\theta\right)}$

Once

\text{sec}(-\theta)=\text{sec}(\theta)

And, \text{sec}(\theta)=-0.73

$-\frac{1}{\cos \left(\theta\right)}=-\text{sec}(\theta)$

$-\frac{1}{\cos \left(\theta\right)}=-(-0.73)$

$-\frac{1}{\cos \left(\theta\right)}=0.73$

Therefore,

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

3 0
3 years ago
Can two different integers have the same absolute value?
kotegsom [21]
8 and -8 both of their absolute values are 8
6 0
3 years ago
Read 2 more answers
PLS HELP ILL GIVE BRAINLIEST!!!!!!!!
anastassius [24]

Answer:

It says it right there.

the answer that you need is 300

Step-by-step explanation:

Brainiest

8 0
2 years ago
Read 2 more answers
Please answer !!!!!!!!!!!!!!!!!!! Will mark brainliest !!!!!!!!!!!!!!!!!!!!!!!!!
xxTIMURxx [149]
Since it is a right angle you would subtract 57 from 90 because both angles added together are 90°. 90-57= 33°
8 0
3 years ago
The point (0, 0) is a solution to which of these inequalities? A. Y - 7 &lt; 2 x - 6 B. Y - 6 &lt; 2 x - 7 C. Y + 7 &lt; 2 x - 6
SCORPION-xisa [38]

Answer:

  A.  y - 7 < 2 x - 6

Step-by-step explanation:

When you put the given values into the inequalities, you get ...

  A: -7 < -6 . . . . true

  B: -6 < -7 . . . . false

  C: 7 < -6 . . . . .false

  D: 7 < 6 . . . . . false

4 0
3 years ago
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