Answer:
30
We'll be using the 5 numbers in your question.
In order to solve this problem, we need to know what range is.
The range is the spread of your data from the <u>lowest</u> to the <u>highest</u> value.
In order to find the range, we need to order the values from least to greatest.
Note: No picture of the stem-and-leaf plot is given in the question.
From least to greatest:
2, 5, 14, 19, 32.
Next, find the maximum and the minimum values.
Minimum: 2
Maximum: 32
Lastly, subtract the maximum and the minimum:
32-2=30.
Your range is 30.
The internet connection types that is being used is DSL (Digital Subscriber Line).
<h3>What is
DSL (Digital Subscriber Line)?</h3>
DSL is a type of broadband internet service that uses existing copper telephone wires to transmit data. DSL can provide high-speed internet access, typically ranging from 1 Mbps to 100 Mbps, depending on the distance from the service provider and the quality of the wiring. DSL can also allow users to make analog phone calls over the same line at the same time, because DSL uses a different frequency band than voice signals. DSL requires a special modem that can separate the data and voice signals and connect to the computer and the phone.
Some advantages of DSL are:
- It is always-on, meaning there is no need to dial up or wait for a connection.
- It is relatively inexpensive and widely available in urban and suburban areas.
- It does not interfere with the normal use of the telephone line.
Some disadvantages of DSL are:
- It is not available in some rural or remote areas, where the distance from the service provider is too far or the wiring is too old or damaged.
- It can be affected by environmental factors, such as noise, weather, or electrical interference.
- It can have variable speeds and performance, depending on the traffic and congestion on the network."
Learn more about DSL (Digital Subscriber Line) from
brainly.com/question/14599737
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For number 15 it is 66,000
Each point should satisfy the equation of the line it belongs to.
This means that:
for the equation of the first line (y=x+b), the point (p,r) satisfies this equation, thus: r = p + b ....................> equation I
for the equation of the second line (y=2x+b), the point (2p,5r) satisfies this equation, thus: 5r = 4p + b ...................> equation II
Subtract equation I from equation II to eliminate the constant b:
5r-r = 4p+b-p-b
4r = 3p
Thus, r/p = 3/4