Phillip saves $8.00 a month. how long would it take him to save at least $60.

Mathematics

2 answers:

Alex73 [517]4 years ago

4 0

It would take Phillip 7 monthes and 4 days to earn 60$$$

blsea [12.9K]4 years ago

3 0

$480.00= 6 months is how long it would take him to save up

You might be interested in

20 CHILDREN WENT TO A CAFE FOR LUNCH.14 CHILDREN ATE FISH BURGERS. 10 CHILDREN ATE CHICKEN BURGERS. HOW MANY CHILDREN ATE BOTH F

Ber [7]

If there are 20 children that went to eat lunch, and 14 of them ate fish burgers, and 10 ate chicken burgers, you could make a line graph with 20 points and color the kids who ate fish burgers yellow and the one who ate chicken burgers blue. The green where they overlapped, and 10 of them over lapped, meaning that <u>10 children ate both fish and chicken burgers. </u>Hope I helped!

6 0

3 years ago

Compute the total cost of the meal to the nearest cent: meal costs $24.62 plus 6% tax and 15% tip.

matrenka [14]

The total cost of the meal is $30.02

Step-by-step explanation:

Given,

Cost of meal = $24.62

Tax = 6%

Tax amount = 6% of cost of meal

$Tax\ amount=\frac{6}{100}*24.62\\Tax\ amount=\frac{147.72}{100}\\Tax\ amount=\$1.48$

Cost after sales tax = 24.62+1.48 = $26.10

Tip = 15%

Tip amount = 15% of cost after sales tax

$Tip\ amount=\frac{15}{100}*26.10\\\\Tip\ amount=\frac{391.5}{100}\\Tip\ amount=\$3.92$

Total cost of meal = Cost after sales tax + Tip amount

Total cost of meal = 26.10+3.92 = $30.02

The total cost of the meal is $30.02

Keywords: percentage, sales tax

Learn more about percentages at:

#LearnwithBrainly

7 0

3 years ago

Eight rooks are placed randomly on a chess board. What is the probability that none of the rooks can capture any of the other ro

Brums [2.3K]

Answer:

9.11*10^-4 %

Step-by-step explanation:

To find the probability, you simply need to find the possible outcomes that allows no rooks to be in danger, and the possible amount of ways to place the rooks.

For the first outcome, you start by putting 1 rook in the first columns, you have 8 possible rows to do this. The next rook in the next column will only have 7 possible rows, as you have to exclude the one where the previous rook is located. The next rook, 6 possibilities, the next 5, and so on. So we conclude that the total amount of ways so that none of the rooks can capture any of the other rooks is 8*7*6*5*4*3*2*1 = 8! = 40320

In order to find the total amount of ways to place the rooks, you can just use a combinatoric:

$\left[\begin{array}{ccc}64\\8\end{array}\right]= \frac{64!}{8!(64-8)!} = 4.43*10^9$