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marysya [2.9K]
3 years ago
14

Help a brother out!!! Math prom worth 20!! And explain please

Mathematics
1 answer:
Reil [10]3 years ago
5 0
A.

ratio 1 to 1

alright
find the distance between the x values and the y values and seperate each into that ratio
1:1
A to B is (6,12) to (15,-4)
disatnce from 6 to 15 is 9, ratio would be 4.5:4.5=1:1
distance from 12 to -4 is 16, ratio would be 8:8=1:1
so the point would be (4.5,8)




b.
5:2
5+2=7
alright
A to C
(6,12) to (20,12)
distance from 6 to 20 is 14, 14/7=2, 2 times 5=10
distance from 12 to 12=0, so same coordinate
the point is (10,12)


c.
2+3=5

C to B
C is (20,12) and B is (15,-4)
distance from 20 to 15 is 5, so 2 is the x value
distance from 12 to -4 is 16, 16/5 times 2=32/5
the point is (2,32/5)
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3 years ago
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from the set {-512,-8,8} ,use substitution to determine which value of x makes the equation true -64x=-1,152
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3 years ago
The graph below represents the solution set of which inequality?
natulia [17]

Answer:

option: B (x^2+2x-8) is correct.

Step-by-step explanation:

We are given the solution set as seen from the graph as:

(-4,2)

1)

On solving the first inequality we have:

x^2-2x-8

On using the method of splitting the middle term we have:

x^2-4x+2x-8

⇒  x(x-4)+2(x-4)=0

⇒ (x+2)(x-4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x+2>0 and x-4

i.e. x>-2 and x<4

so we have the region as:

(-2,4)

Case 2:

x+2 and x-4>0

i.e. x<-2 and x>4

Hence, we did not get a common region.

Hence from both the cases we did not get the required region.

Hence, option 1 is incorrect.

2)

We are given the second inequality as:

x^2+2x-8

On using the method of splitting the middle term we have:

x^2+4x-2x-8

⇒ x(x+4)-2(x+4)

⇒ (x-2)(x+4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x-2>0 and x+4

i.e. x>2 and x<-4

Hence, we do not get a common region.

Case 2:

x-2 and x+4>0

i.e. x<2 and x>-4

Hence the common region is (-4,2) which is same as the given option.

Hence, option B is correct.

3)

x^2-2x-8>0

On using the method of splitting the middle term we have:

x^2-4x+2x-8>0

⇒ x(x-4)+2(x-4)>0

⇒ (x-4)(x+2)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x+2>0 and x-4>0

i.e. x>-2 and x>4

Hence, the common region is (4,∞)

Case 2:

x+2 and x-4

i.e. x<-2 and x<4

Hence, the common region is: (-∞,-2)

Hence, from both the cases we did not get the desired answer.

Hence, option C is incorrect.

4)

x^2+2x-8>0

On using the method of splitting the middle term we have:

x^2+4x-2x-8>0

⇒ x(x+4)-2(x+4)>0

⇒ (x-2)(X+4)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x-2 and x+4

i.e. x<2 and x<-4

Hence, the common region is: (-∞,-4)

Case 2:

x-2>0 and x+4>0

i.e. x>2 and x>-4.

Hence, the common region is: (2,∞)

Hence from both the case we do not have the desired region.

Hence, option D is incorrect.




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Answer:

4 1/3

Step-by-step explanation:

hope this helps!

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den301095 [7]

The true statement about the circle with center P is that triangles QRP and STP are congruent, and the length of the minor arc is 11/20π

<h3>The circle with center P</h3>

Given that the circle has a center P

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From the question, we understand that QR = ST.

This implies that triangles QRP and STP are congruent.

i.e.  △QRP ≅ △STP is true

<h3>The length of the minor arc</h3>

The given parameters are:

Angle, Ф = 99

Radius, r = 1

The length of the arc is:

L = Ф/360 * 2πr

So, we have:

L = 99/360 * 2π * 1

Evaluate

L = 198/360π

Divide

L = 11/20π

Hence, the length of the minor arc is 11/20π

Read more about circle and arcs at:

brainly.com/question/3652658

#SPJ1

5 0
2 years ago
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