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Advocard [28]
3 years ago
5

The tax rate is 3.9% What is the tax on 42$? Round to the nearest hundredth

Mathematics
1 answer:
Leya [2.2K]3 years ago
5 0
The answer is 45.9 you Add it
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Factors of 4x^3-14x^2+12x
IRISSAK [1]

Step-by-step explanation:

4x³ - 14x² + 12x

= 2x[2x² - 7x + 6]

= 2x[(2x-3)(x-2)]

= 2x(2x-3)(x-2)

7 0
2 years ago
The size of airmail packages is it continuous or discrete?
valina [46]
The answer is d<span>iscrete.</span>
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2 years ago
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How to write 899,501 in expanded form
adell [148]
800,000+90,000+9,000+500+1
5 0
3 years ago
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Last month you purchased 6 individual songs and 1 albums for a total of $21.99.
Annette [7]

Answer:

Song =$1.50 Album =$12.99

Step-by-step explanation:

Lets assume Individual songs = x

albums=y

6x + y = 21.99-------- y= 21.99- 6x

4x + 3y= 44.97

Replace y in the second equation

4x+ 3(21.99-6x) = 44.97

4x +65.97- 18x = 44.97

14x= 21

x = 1.50

y= 21.99- (6*1.50)

= 12.99

7 0
3 years ago
Assume that the population of human body temperatures has a mean of 98.6 degrees F and a standard deviation of 0.62 degrees F. I
dimulka [17.4K]

Answer:

0% probability of getting a mean temperature of 98.2 degrees F or lower.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 98.6, \sigma = 0.62, n = 106, s = \frac{0.62}{\sqrt{106}} = 0.06

Find the probability of getting a mean temperature of 98.2 degrees F or lower.

This is the pvalue of Z when X = 98.2. So

Z = \frac{X - \mu}{s}

Z = \frac{98.2 - 98.6}{0.06}

Z = -6.67

Z = -6.67 has a pvalue of 0.

So there is a 0% probability of getting a mean temperature of 98.2 degrees F or lower.

8 0
2 years ago
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